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Ksenya-84 [330]
3 years ago
15

The wave frequency is where 1 hertz equals 1 wave passed a fixed point in 1 second.

Physics
1 answer:
ahrayia [7]3 years ago
3 0

                     (10 waves) / (5 sec) 

                 =  (10/5) (wave/sec)

                 =      2      per sec

                 =      2        Hz .
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Newton's 2nd law: F = m * a ⇒ a = F / m
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3 years ago
A 45 g bug is hovering in the air. A gust of wind
MariettaO [177]

The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

  • Mass of the bug, m = 45 g
  • Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
  • Displacement of the bug, r = (8.0î - 8.0j) m

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

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Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

Learn more here:brainly.com/question/19498865

5 0
3 years ago
Five equal negative charges are uniformly spaced in a semicircular
balu736 [363]

Answer:

The direction is that of a 3rd quadrant angle

Explanation:

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6 0
4 years ago
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and
mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

f=288 Hz

v=1.45\cdot 10^3 m/s

Substituting into the equation, we find the wavelength:

\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m

3 0
4 years ago
Can someone help me with science:
Oliga [24]

Answer:

trur

Explanation:

gvidttcyhjddgdhjfjdjsjs

6 0
3 years ago
Read 2 more answers
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