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3 years ago

Photo attached: please help!!!

Physics

1 answer:

Tasya [4]3 years ago

3 0

Answer:

The center of mass changes

Explanation:

The higher the center of mass the more likely things are to topple over but the lower it is the more likely to stay put when all 4 wheels are down .

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An object is tracked by a radar station and found to have a position vector given by r = (4570-160 t) i + 2930j + 130k , with r

Kipish [7]

Answer:

a)P= -4800 i

b)F= 0

Explanation:

Given that

r = (4570-160 t) i + 2930 j + 130 k

We know that velocity is rate of change of the space vector.

V= dr/dt

r = (4570-160 t) i + 2930 j + 130 k

dr/dt= -160 i + 0 + 0

dr/dt= -160 i

V= -160 i

It means that velocity is in only x-direction

We also know that acceleration is the rate of change of velocity .

a= dV/dt

V= -160 i

dV/dt=0

So we can say that acceleration is zero.

a= 0

From Second law of Newton'

Force = Mass x acceleration

F= 300 x 0

F= 0

We know that linear momentum P

P = m V

Given that m= 300 kg

P = 300 x (-160 i)

P= -4800 i

6 0

3 years ago

Xavier throws a tennis ball to his friend Olaf at a 20° angle relative to the ground with an initial velocity of 18 m/s. The ten

Svetllana [295]

Ball is thrown at an angle of 20 degree with velocity 18 m/s

so first we will find the two components of the velocity

$v_x = 18 cos20$

$v_x = 16.91 m/s$

similarly for other component

$v_y = 18 sin20$

$v_y = 6.16 m/s$

now the ball will cover horizontal distance of 30 m till it reach to other player

so here we can use the formula of time

$x = v_x * t$

$30 = 16.91 * t$

$t = \frac{30}{16.91}$

$t = 1.77 s$

so it will take 1.77 s to reach the other player

3 0

3 years ago

Tamara exerts a force downward on a chair by sitting on it. Which of the following statements best explains why the chair does n

ValentinkaMS [17]

I think the answer is A

6 0

3 years ago

The cue ball is deflected so that it makes an angle of 30.0° with its original direction of travel.

Alexus [3.1K]

Answer:

(a) θ= 43.89°

(b) $v_{1} = 1.88\sqrt{3} \frac{m}{s}$

$v_{2} = 6.79 \frac{m}{s}$

Explanation:

Ball 1:

$u_{1} = 7.52\frac{m}{s}$

Ball 2:

$u_{2} = 0\frac{m}{s}$

As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:

$\frac{1}{2} m_{1}u_{1}^{2} = \frac{1}{2} m_{1}v_{1}^{2} + \frac{1}{2} m_{2}v_{2}^{2}$

and

$m_{1}u_{1} = m_{1}v_{1} + m_{2}v_{2}$

Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:

$u_{1}^{2} = v_{1}^{2} + v_{2}^{2}$

and

$u_{1} = v_{1} + v_{2}$

This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::

$56.55 = v_{1} ^{2} + v_{2} ^{2}$