A super acid is defined as an acid with acidity greater than 100% pure H2SO4. It can also be defined as a medium in which the chemical potential of the proton is higher than in pure Sulphuric Acid.
Coefficients in a chemical equation express RATIOS between molecules or compounds.
In chemical equations, coefficient refers to those numerical numbers that are usually written at the front of elements' chemical symbols in order to balance the equations. Coefficients tell us the number of a particular element that must react with a specific number of another element in order for certain amount of chemical products to be produced; that is, it provide information about the reaction ratio of reactants and products. For instance, look at this chemical equation: N2 + 3H2 = 2NH3
In the equation given above, the coefficient of N2 is 1, the coefficient of H2 is 3 and the coefficient of NH3 is 2. What this equation is essentially telling us is that, in order to produce two molecules of ammonia, one molecule of nitrogen must react with three molecules of hydrogen. Thus, the equation gives the ratios between the product and the reactants.
Answer is 231.8 K
<em>Explanation</em>
We can use Charle's law to solve this problem.
<span>Charle's law says
"at a constant
pressure, the volume of a fixed amount of gas is directly proportional to its
absolute temperature".
V α T
Where V is the volume and T is the temperature
in Kelvin of the gas. We can use this for two situations as,
V</span>₁/T₁ = V₂/T₂<span>
</span>V₁ = 1.00 L<span>
T</span>₁ =
?<span>
V</span>₂ = 1.10 L<span>
T</span>₂ = 255 K (Since the unit of the given temperature is missing in the question, thought that the given temperature is in Kelvin)<span>
<span>
By applying the
formula,
</span>1.00 L / </span>T₁ = 1.10 L / 255 K
<span>
</span>T₁ =
(1.00 L / 1.10 L) x 255 K<span>
</span>T₁ = 231.8 K
<span>
Hence, the initial temperature is 231.8 K.
</span><span>
Assumption : the pressure of the gas is a constant.
</span>
Density = mass / volume
Thus, Mass of the solution can be expressed as:
Mass of solution = Density of solution × volume of solution
Given- Density of solution = 1.126 g/ml
volume of solution = 20.0 ml
∴ Mass of 14 wt% solution of CaCl2 = (1.126 g/ml) × (20 ml)
= 22.52 g
= 22520 mg
Answer:
Chlorine can be found in Period 3.
Explanation:
Periods on the periodic table are the rows (horizontal sections) that group elements together. By looking across Period 3, you will find Cl (chlorine).
