All categories

2 years ago

The density of benzene at 15 ∘C is 0.8787 g/mL. Calculate the mass of 0.1200 L of benzene at this temperature.

Chemistry

2 answers:

BabaBlast [244]2 years ago

8 0

The mass of 0.1200 L of benzene at 15° Celsius is 105.44 g.

FURTHER EXPLANATION

Density is a measure of how tightly packed the particles of a material are. The more tightly packed the particles, the greater the density and vice versa. Density is also mostly defined as the amount of matter in a given volume or space. The amount of matter corresponds to its mass. Density is an intensive property of matter so it may be used to qualitatively identify an unknown substance.

To determine the mass of benzene, recall the definition of density:

$density = \frac{mass}{volume}$

Since the density and the volume of benzene are given, the mass can be calculated as follows:

$mass = density \times volume$

Before the given volume and density can be plugged into the equation, volume of benzene must first be converted to milliliters.

$0.1200 \ L \times \frac{1000 \ mL}{1 \ L} = \boxed {120 \ mL}$

Plugging into the equation for mass:

$mass = 0.8787 \frac{g}{mL} \times 120 \ mL\\\\\boxed {mass = 105.444 \ g}$

LEARN MORE

Learn more about Dimensional Analysis brainly.com/question/1557970
Learn more about Mole Conversion brainly.com/question/5297200
Learn more about Intensive property brainly.com/question/430934

<em>Keywords: density, unit conversion, benzene</em>

Pavel [41]2 years ago

3 0

Use the density to convert volume into mass.

since the density is in g/ml and the volume was given in Liters, we need to first convert the Liters into mililiters. just multiply by 1000 or move the decimal three times.

0.1200 Liters= 120.0 mL

120.0 mL (0.8787 grams/ 1 mL)= 105 grams

You might be interested in

What describes a phase change

Finger [1]

A phase change is when matter changes to from one state ( solid, liquid, gas, plasma) to another.

3 0

2 years ago

Condensation point and freezing point of argon in KELVIN.

vesna_86 [32]

Answer:

Condensation: 423.3 K

Freezing: 83.96 K

(this is all i could figure out :) hope it helps)

4 0

2 years ago

Are parts of the circulatory system<br> .The<br> , and

Sphinxa [80]

Answer:

The heart and the blood vessels are a part of the circulatory system. The blood vessels include the arteries, veins and capillaries. The lungs are considered to be the pulmonary part of the circulatory system. The heart is the cardiovascular part of the circulatory system and the vessels are the systemic part of the circulatory system. The main function of the circulatory system is to supply all parts of the body with oxygenated blood and to take away the deoxygenated blood from all parts of the body.

8 0

3 years ago

Hydrogen bonds are in the family of Van der Waals forces. They are weaker than ionic and covalent bonds but they cause interesti

-Dominant- [34]

Answer:

The answer is B. Van der Waals forces are weaker than ionic and covalent bonds.

Explanation:

In general, if we arrange these molecular forces from the strongest to weakest, it would be like this:

Covalent bonds > Ionic bonds > Hydrogen bonds > Dipole-Dipole Interactions > Van der Waals forces

Covalent bonds are known to have the strongest and most stable bonds since they go deep and into the inter-molecular state. A diamond is an example of a compound with this characteristic bond.

Ionic bonds are the next strongest molecular bond following covalent bonds. This is due to the protons and electrons causing an electro-static force which results to the strong bonds. An example would be Sodium Chloride (NaCl), which when separated is Na⁺ and Cl⁻.

Van der Waals forces, also known as Dispersion forces, are the weakest type of molecular bonds. They are only formed through residual molecular attractions when molecules pass by each other. It doesn't even last long due to the uneven electron dispersion. It can be made stronger by adding more electrons in the molecule. This kind of molecular bonds appear in non-polar molecules such as carbon dioxide.

HOPE THIS HELPS!!!!!!!!!!!!!!

///////////////////////////////////////////////////////////////////////////////////////////

7 0

2 years ago

An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t

topjm [15]

Answer:

$\boxed{3}$

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

$\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )$

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

$\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}$

Data:

$n_{f} = 2$

λ = 657 nm

Calculation:

$\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}$

7 0

2 years ago