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sveticcg [70]
3 years ago
9

Calculate the ph of a solution that is 0.26 m in hf and 0.12 m in naf.

Chemistry
1 answer:
DochEvi [55]3 years ago
5 0
When a mixture consists of a weak acid, such as HF, and its corresponding salt, NaF, this is an acid buffer. So, we can use the equation as written below:

pH = pKa + log(salt/acid)

For HF, the pKa = 3.17

Thus,
pH = 3.17 + log(0.12/0.26)
<em>pH = 2.83</em>
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You already converted mass to moles for the reactants now convert mass to moles for the product, copper 0.71 g Cu equals
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Answer: 0.011 moles.

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3 0
4 years ago
How many moles are in 1.93x1023 particles of Na3PO4?
Tresset [83]

Answer:

<h3>The answer is 0.32 moles</h3>

Explanation:

To find the number of moles given the number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.93 × 10²³ particles

We have

n =  \frac{1.93 \times  {10}^{23} }{6.02 \times  {10}^{23 } }  \\  = 0.320598006...

We have the final answer as

<h3>0.32 moles</h3>

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