Answer:
a) The total time of the trip is 4.05 h.
b) The average speed of the car is 12.35 mi/h.
c) The total time of the trip is 1.69 h.
Explanation:
Hi there!
a) The equation of traveled distance for a car traveling at constant speed is the following:
x= v · t
Where:
x = traveled distance.
v = velocity.
t = time.
Solving the equation for t, we can find the time it takes to travel a given distance "x" at a velocity "v":
x/v = t
So, the time it takes the car to travel the first half of the distance will be:
t1 = 25.0 mi / 7.00 mi/h
And for the second half of the distance:
t2= 25.0 mi / 52.00 mi / h
The total time will be:
total time = t1 + t2 = 25.0 mi / 7.00 mi/h + 25.0 mi / 52.00 mi / h
total time = 4.05 h
The total time of the trip is 4.05 h.
b) The average speed (a.s) is calculated as the traveled distance (d) divided by the time it takes to travel that distance (t). In this case, the traveled distance is 50 mi and the time is 4.05 h. Then:
a.s = d/t
a.s = 50 mi / 4.05 h
a.s = 12.35 mi/h
The average speed of the car is 12.35 mi/h
c) Let's write the equations of traveled distance for both halves of the trip:
For the first half, you traveled a distance d1 in a time t1 at 7.00 mph:
7.00 mi/h = d1/t1
Solving for d1:
7.00 mi/h · t1 = d1
For the second half, you traveled a distance d2 in a time t2 at 52.00 mph.
52.00 mi/h = d2/t2
52.00 mi/h · t2 = d2
We know that d1 + d2 = 50 mi and that t1 and t2 are equal to t/2 where t is the total time:
d1 + d2 = 50 mi
52.00 mi/h · t/2 + 7.00 mi/h · t/2 = 50 mi
Solving for t:
29.5 mi/h · t = 50 mi
t = 50 mi / 29.5 mi/h
t = 1.69 h
The total time of the trip is 1.69 h.
