Ask question

Ask question

All categories

3 years ago

5

A thermometer is placed into a flask of water with pieces of ice and reads 273.15. Which temperature scale is being used? A. Kel

vin B. Celsius C.Centigrade
D. Fahrenheit

2 answers:

Aleks [24]3 years ago

8 0

A.) Kelvin bc it it wouldnt make sense for the other three options plus options B.) and C.) are the same :)

zzz [600]3 years ago

6 0

A. Kelvin. It is 32 degrees fahrenheit

You might be interested in

PLeAsE hElp <br> What is the kinetic energy of 14 Kg traveling at a velocity of 3m/s east

harkovskaia [24]

Answer:

Please see the given attachment.

Explanation:

Stay safe, stay healthy and be blessed.

Thank you.

<h2><em><u>PLEASE</u></em><em><u> </u></em><em><u>MARK</u></em><em><u> </u></em><em><u>ME</u></em><em><u> </u></em><em><u>AS </u></em><em><u>BRAINLEST</u></em><em><u>.</u></em></h2>

4 0

2 years ago

Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table.

emmainna [20.7K]

C. It doubles I hope this helps and good luck

6 0

3 years ago

Read 2 more answers

3. What is the relationship among wave speed, wavelength, and frequency?

Rus_ich [418]

Answer:

Wave speed is related to both wavelength and wave frequency. Wavelength is the distance between two corresponding points on adjacent waves. Wave frequency is the number of waves that pass a fixed point in a given amount of time. This equation shows how the three factors are related:

Speed = Wavelength x Wave Frequency

Explanation:

4 0

2 years ago

Why is your State have dimensions

Ilya [14]

Answer:

not sure you

Explanation:

8 0

3 years ago

Determine the average value of the translational kinetic energy of the molecules of an ideal gas at (a) 27.8°C and (b) 143°C. Wh

Alinara [238K]

Answer:

a) $k_{avg}=6.22\times 10^{-21}$

b) $k_{avg}=8.61\times 10^{-21}$

c) $k_{mol}=3.74\times 10^{3}J/mol$

d) $k_{mol}=5.1\times 10^{3}J/mol$

Explanation:

Average translation kinetic energy ( $k_{avg}$ ) is given as

$k_{avg}=\frac{3}{2}\times kT$ ....................(1)

where,

k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K

T = Temperature in kelvin

a) at T = 27.8° C

or

T = 27.8 + 273 = 300.8 K

substituting the value of temperature in the equation (1)

we have

$k_{avg}=\frac{3}{2}\times 1.38\times 10^{-23}\times 300.8$

$k_{avg}=6.22\times 10^{-21}J$

b) at T = 143° C

or

T = 143 + 273 = 416 K

substituting the value of temperature in the equation (1)

we have

$k_{avg}=\frac{3}{2}\times 1.38\times 10^{-23}\times 416$

$k_{avg}=8.61\times 10^{-21}J$

c ) The translational kinetic energy per mole of an ideal gas is given as:

$k_{mol}=A_{v}\times k_{avg}$

here $A_{v}$ = Avagadro's number; ( 6.02×10²³ )

now at T = 27.8° C

$k_{mol}=6.02\times 10^{23}\times 6.22\times 10^{-21}$

$k_{mol}=3.74\times 10^{3}J/mol$

d) now at T = 143° C

$k_{mol}=6.02\times 10^{23}\times 8.61\times 10^{-21}$

$k_{mol}=5.1\times 10^{3}J/mol$

8 0

3 years ago