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zaharov [31]
3 years ago
10

A block lies on a frictionless floor. a force of 5 n pulls toward the east while a force of 4 n pulls toward the north. what is

the magnitude of the net force on the block?

Physics
1 answer:
sveticcg [70]3 years ago
3 0

Given below the arrangement of loading on the larger boat by two tug boats.

F₁ = 5 N

F₂ = 4 N

Angle between them θ = 90⁰

Resultant between two vectors, F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta }

Substituting

   F = \sqrt{5^2+4^2+2*5*4*cos 90} \\ \\ = 6.403 N

So magnitude of the net force on the block = 6.403 N

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A 244.0 N block is at rest on a flat, frictionless table. A hooked cable applies an upward force of 24.0 N on the block. What is
blagie [28]

Answer:

268N

Explanation:

The upward force acting on the block are the reaction and the hooked table..

The total normal force acting = normal reaction + 24N

Note that the normal reaction is always equal the weight of the table

Hence the normal force acting in the block is 244.0+24 = 268.0N

4 0
3 years ago
How does an inclined plane affect the effort needed to move a load vertically?
VashaNatasha [74]

If we pull an object vertically upwards then we need to apply a force which is equal in the magnitude of the weight of the object

F = mg

now when we pull the same object upwards along an inclined plane with angle then we require a force which will balance the component of weight along the inclined

so it is given as

F' = mgsin\theta

so as if we compare the two forces we can say that since the value of sine is always less than 1 for an angle less than 90 degree

so in the 2nd case when we pull the object along the inclined plane it will require less effort

so correct answer is

<em>A. reduce effort</em>

5 0
3 years ago
Please I need HELP WITH THIS QUESTION!!!
JulsSmile [24]
Oil, grease and dry lubricants
8 0
3 years ago
At an altitude of 5000 m the rocket's acceleration has increased to 6.9 m/s2 . What mass of fuel has it burned?
sergey [27]

1) Initial upward acceleration: 6.0 m/s^2

2) Mass of burned fuel: 0.10\cdot 10^4 kg

Explanation:

1)

There are two forces acting on the rocket at the beginning:

- The force of gravity, of magnitude F_g = mg, in the downward direction, where

m=1.9\cdot 10^4 kg is the rocket's mass

g=9.8 m/s^2 is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

T=3.0\cdot 10^5 N

According to Newton's second law of motion, the net force on the rocket must be equal to the product between its mass and its acceleration, so we can write:

T-mg=ma (1)

where a is the acceleration of the rocket.

Solving for a, we find the initial acceleration:

a=\frac{T-mg}{m}=\frac{3.0\cdot 10^5-(1.9\cdot 10^4)(9.8)}{1.9\cdot 10^4}=6.0 m/s^2

2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

a'=6.9 m/s^2

The reason for this increase is that the mass of the rocket has decreased, because the rocket has burned some fuel.

We can therefore rewrite eq.(1) as

T-m'g=m'a'

where

m' is the new mass of the rocket

Re-arranging the equation and solving for m', we find

m'=\frac{T}{g+a}=\frac{3.0\cdot 10^5}{9.8+6.9}=1.8\cdot 10^4 kg

And since the initial mass of the rocket was

m=1.9 \cdot 10^4 kg

This means that the mass of fuel burned is

\Delta m = m-m'=1.9\cdot 10^4 - 1.80\cdot 10^4 = 0.10\cdot 10^4 kg

3 0
3 years ago
Which type of energy is stored in a capacitor? electric potential energy chemical energy gravitational energy heat energy
Tom [10]

Energy stored in a capacitor is Electric Potential Energy. Capacitor is device used for storing energy. The work done to charge is a capacitor is stored in it in the form of Electrical potential energy. Electrical potential energy is defined as capacity to do work due to the position change. For example, we know fans have capacitor installed in it. When we turn off the fan, it continue moving using the electrical energy stored in the capacitor.

6 0
3 years ago
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