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zaharov [31]
3 years ago
10

A block lies on a frictionless floor. a force of 5 n pulls toward the east while a force of 4 n pulls toward the north. what is

the magnitude of the net force on the block?

Physics
1 answer:
sveticcg [70]3 years ago
3 0

Given below the arrangement of loading on the larger boat by two tug boats.

F₁ = 5 N

F₂ = 4 N

Angle between them θ = 90⁰

Resultant between two vectors, F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta }

Substituting

   F = \sqrt{5^2+4^2+2*5*4*cos 90} \\ \\ = 6.403 N

So magnitude of the net force on the block = 6.403 N

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OLEGan [10]

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The vertical position at time t is given by

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The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

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30N in the direction the 45N acts.

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