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2 years ago

If you run at 1.7 m/s FORWARD ,how does this affect the speed of a ball that you throw?

1 answer:

8 0

We have a problem about conservation and velocity, we will find that it does affect the speed of the ball, increasing it by 1.7m/s.

There is something called momentum, which we can define as the "quantity of movement", and we can simply write as the product between velocity and mass.

The momentum is conservative, then we have conservation of momentum.

This means that when you run whit the ball in your hands, the momentum of the ball will be equal to your velocity times the mass of the ball, and this must conserve after you throw the ball.

Now with this idea in mind, this means that if you run with a velocity V, and you throw the ball with a velocity V', the velocity of the ball when it leaves your hand will be:

V + V'.

So, if you run with a velocity of 1.7m/s forward and you throw the ball (assuming in the same direction) the speed of the ball will be 1.7m/s larger than if you were to throw it standing still.

If you want to learn more, you can read:

brainly.com/question/13639113

You might be interested in

A football player runs 20 meters North of a football field, and then 15 meters East. The total motion lasted 15 seconds. What wa

vlada-n [284]

Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds

Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
Ave. Speed = 2 1/3 meters per second

4 0

2 years ago

You cheated on a test and you know it was the wrong thing to do according to the psychology theory what helped you know this

Alexandra [31]

Answer:

You cheated on a test, and you know it was the wrong thing to do. According to the psychoanalytic theory, what helped you know this?

The id controlled your biological response and made you sweaty because you were scared of getting caught.

The superego acted as your moral conscience; you just knew that it wasn't right to cheat.

The ego made you feel guilty as a defense mechanism. both B and C

Explanation:

the answer is both B,C

6 0

3 years ago

What is a gravitational field and how its strength be measured

Yakvenalex [24]

A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to
$F= \frac{GM}{r^2} m$
where $G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2}$ is the gravitational constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive.

A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
$F=ma$
but since
$F= \frac{GM}{r^2} m$
we can write
$a = \frac{GM}{r^2}$
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.

5 0

3 years ago

An engine pulls a train of 20 freight cars, each having a mass of 4.900 × 104 kg, with a constant force. The cars move from rest

bixtya [17]

Answer:

The force with which the tenth car pulls the eleventh one is called tension and is equal to:

T=119715.91 N

Explanation:

The force (F) with which the tenth car pulls the eleventh one is called tension and its direction is the X-direction or horizontal. According to Newton's Second Law of motion:

$\sum F=ma$

That is, the force of the car is equal to the acceleration (a) times its mass (m). The acceleration is the change in the velocity divided by the time (i is for initial and f is for final).

$a=\frac{v_f-v_i}{t_f-t_f}$

Using Newton's second law:

To find the forces, you have to solve the equilibrium in X-direction:

$\sum F_x=T=ma_x$

Now you can substitute the accelertion in terms of velocity and time:

$\sumF_x=T=ma_x=m\frac{v_f-v_i}{t_f-t_i}$

Solve the equation using the data from the problem, remember that the mass of the object is 10 times the mass of one car because the 10th car has to pull all the other cars:

$T=m\frac{v_f-v_i}{t_f-t_i}=(10)*(4.900 \times 10^4 kg)(\frac{4.3 m/s}{17.60s})\\T=119715.91 N$