A or B... I mean when lava is poured out to the surface, heat and soilica content may play a role... That's what I think sorry :(
Explanation:
For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.
Three known temperature scales;
- Kelvin scale
- Celcius scale
- Fahrenheit scale
Kelvin scale Celcius scale Fahrenheit scale
Freezing point 273K 0°C 32°F
Melting point 373K 100°C 212°F
Answer:
L = 8694 Kg.m²/s
Explanation:
r = 270 ĵ m
v = 14 î m/s
m = 2.3 kg
θ = 90º
L = ?
We can apply the equation
L = m*v*r*Sin θ
L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s
Answer:
The answer to your question is 5.4 cm
Explanation:
This problem refers to calculate the change in length in one dimension due to a change in temperature.
Data
α = 12 x 10⁻⁶
Lo = 150 meters
ΔT = 30 °C
Formula
ΔL/Lo = αΔT
solve for ΔL
ΔL = αLoΔT
Substitution
ΔL = (12 x 10⁻⁶)(150)(30)
Simplification
ΔL = 0054 m = 5.4 cm
Oh my lord lol I was do ready to help then I saw numbers