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kotegsom [21]
3 years ago
13

The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)=−C6/x6, where C6 is a positive

constant. Part A What is the force that one atom exerts on the other? Express your answer in terms of C6 and x. Fx = nothing Request Answer Part B Is this force attractive or repulsive? Is this force attractive or repulsive? attractive repulsive
Physics
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

The correct answer will be "-\frac{6C_{6}}{x^{7}}". The further explanation is given below.

Explanation:

The potential energy will be,

⇒  U(x)= -\frac{C_{6}}{x^6}

The expression of force will be,

⇒  F=-\frac{dU(x)}{dx}

⇒      =-(C_{6}(-6)x^{-7})

⇒      =-\frac{6C_{6}}{x^{7}}

Force seems to be appealing because the expression has been negative. It therefore means that the force or substance is acting laterally in on itself.

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malfutka [58]

The mechanical advantage of a simple machine is the measure of its amplified force gain.

The mechanical advantage  is defined as the force amplified by a machine to the force required to generate such output.

Mathematically\ mechanical\ advantage\ MA=\frac{F_{o}} {F_{i}}

F_{o} \ and\ F_{i} are the amplified force and applied force. We may also consider them as output and input force.          


In the given question, the force given to the steering wheel is 50 N.

The output force produced by the steering wheel is 3750 N.

Hence the mechanical advantage will be-

                               MA=\frac{F_{o}} {F_{i}}

                                       =\frac{3750\ N}{50\ N}

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3 0
3 years ago
How am I supposed to solve this?
RSB [31]

Answer:

4.02 km/hr

Explanation:

5 km/hr = 1.39 m/s

The swimmer's speed relative to the ground must have the same direction as line AC.

The vertical component of the velocity is:

uᵧ = us cos 45

uᵧ = √2/2 us

The horizontal component of the velocity is:

uₓ = 1.39 − us sin 45

uₓ = 1.39 − √2/2 us

Writing a proportion:

uₓ / uᵧ = 121 / 159

(1.39 − √2/2 us) / (√2/2 us) = 121 / 159

Cross multiply and solve:

159 (1.39 − √2/2 us) = 121 (√2/2 us)

220.8 − 79.5√2 us = 60.5√2 us

220.8 = 140√2 us

us = 1.115

The swimmer's speed is 1.115 m/s, or 4.02 km/hr.

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