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tensa zangetsu [6.8K]
3 years ago
7

How many formula units is 213 g of PbCl2?

Chemistry
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

4.61 x 10^23

Explanation: Convert 213g of PbCl2 to mol, which is 0.7658950184462004, multiply 0.765 with 6.022 x 10^23.

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What mass of water is needed to raise the temperature by 15 degrees C using 165 Joules of energy
Lady bird [3.3K]

Mass of the water is 2.63 g.

<u>Explanation:</u>

Mass of the water, m = ? g

Temperature, ΔT = 15 °C

Heat absorbed, q = 165 J

Specific heat capacity, c = 4.18 J / g °C

q = m × c × ΔT

Now, we have to find the mass of the water by rewriting the above equation as,

m =  $\frac{q}{c\times dT }

Now Plugin the above values in the equation as,

m = $\frac{165}{4.18\times15}

 =  2.63 g

So the mass of the water is found as 2.63 g.

8 0
3 years ago
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A graduated cylinder has 65 mL of water at 25 oC. When 45.0 g of an unknow solid is dropped into the graduated cylinder, the liq
inysia [295]

Answer:

4.17 g/mL

Explanation:

In order to determine the density of the solid, we need to know both its mass and its volume.

<em>The mass </em>is already given to us by the problem, 45.0 g.

As for <em>the volume</em>, we can determine it by using <u>Archimedes' principle.</u> It states that the volume of water displaced by an object when submerged is equal to the object's volume.

  • Water displaced = 75.8 mL - 65 mL = 10.8 mL

Finally we <u>calculate the density</u> of the solid:

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3 years ago
What are the properties of the aluminum in the can
arlik [135]
Solid, malleable, and can be crushed
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Be<br><br> Name the element.<br><br> Number of shells?<br><br> Valence electrons?
Vedmedyk [2.9K]

Answer:

Name the element: Beryllium

Number of shells:  4

Valence electrons: 2

Explanation:

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3 years ago
The compound tyrosine contains 59.66% C, 6.12% H, 7.73% N, and 26.49% O by mass. What is the empirical formula of tyrosine?
ycow [4]

Answer: C9H11O3N

Explanation:

The percentage by mass of each element is divided by its relative atomic mass. The lowest ratio is now observed. Each ratio is now divided by this lowest ratio and approximated to whole numbers. All these are shown in detail in the image attached.

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4 years ago
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