Initial moles of CH₃COOH = 1.00 x 0.0100 = 0.0100 mol
Initial moles of CH₃COONa = 1.00 x 0.100 = 0.100 mol
Let a be the volume of HNO₃ that must be added
Moles of HNO₃ added = a/1000 x 10.0 = 0.01a mol
CH₃COONa + HNO₃ => CH₃COOH + NaNO₃
Moles of CH₃COOH = 0.0100 + 0.01a
Moles of CH₃COONa = 0.100 - 0.01a
pH = pKa + log([CH₃COONa]/[CH₃COOH])
= pKa + log(moles of CH₃COONa/moles of CH₃COOH)
5.05 = 4.75 + log((0.100 - 0.01a)/(0.0100 + 0.01a))
log((0.100 - 0.01a)/(0.0100 + 0.01a)) = 0.3
(0.100 - 0.01a)/(0.0100 + 0.01a) = 10^0.3 = 2.0
0.03 a = 0.08
a = 2.67
<span>Volume of HNO3 = a = </span>2.13 mL
Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
In the space of 1 liter, methane gas (ch4) is reacted with 6 moles of water vapor according to the reaction: if at equilibrium state is obtained 4 moles of hydrogen gas, how many moles of methane gas is needed for the equilibrium reaction?
the reaction is
CH4(g) + 2H2O(g) ----> CO2(g) + 4H2 (g)
Kc = 16 / 3
Kc = [CO2] [H2]^4 / [CH4] [H2O]^2
given :
equilibrium concentration
[H2] = 4 moles
so equilibrium concentration of CO2 must be 1 mole
equilibrium concentration of H2O = 6 - 2 = 4
putting values
16 /3 = [1] [4]^4 / [CH4] [4]^2
[CH4] = 0.333 moles
so moles of CH4 required = 1.33 moles
Answer:
Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they're ... Group A is given the special juice to drink while they work. Group ... 1. Control Group. Group B. 2. Independent Variable. volume of special juice.
Explanation:
we can clear specific heat:
