2NaClO₃ → 2NaCl + 3O₂
mole ratio of NaClO₃ to O₂ is 2 : 3
∴ if moles of NaClO₃ = 12 mol
then moles of O₂ =
= 18 mol
Mass of O₂ = mol of O₂ × molar mass of O₂
= 18 mol × 16 g/mol
= 288 g
So I wasn't sure which equation to use since you did not specify so I just used the decomposition reaction. If you should have used another reaction then just follow the same steps and you'll get your answer.
Yes, because nothing has changed. The same ingredients are used and if one reaction happened in a a bag then why wouldn’t it happen in a container?
Because of Bronze's high...... what?
Answer:
THE MOLAR MASS OF THE UNKNOWN COMPOUND IS 242.02 g/mol.
Explanation:
First:
Calculate the change in freezing point:
Freezing point of pure benzene = 5.5°C
Change in temperature = 5.5 - 3.06 = 2.44 °C
Second:
Using the formula:
Δt = i Kf m
Let's assume i = 1
Kf = 5.12 °C/m
M = x / 0.250 kg of benzene
Then we can calculate x which is the molarity
Re-arranging the formula, we have:
m = Δt / i Kf
x / 0.250 = 2.44 / 1 * 5.12
x = 2.44 * 0.250 / 5.12
x = 0.61 / 5.12
x = 0.119 M
Since it is well known that molarity is the mass of a substance divided by its molar mass. We can then calculate the molar mass.
Molar mass = Mass / molarity
Molar mass = 28.8 g / 0.119 M
Molar mass =242.02 g/mol
Hence, the molar mass of the unknown molecular compound is 242.02 g/mol.
Answer:
4 mL
Explanation:
Use the density formula, d = m/v
Plug in the density and mass to solve for v:
4 = 16/v
4v = 16
v = 4
So, the volume is 4 mL