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RUDIKE [14]
4 years ago
9

Calculate the mass percent (m/m) of a solution prepared by dissolving 55.84 g of nacl in 152.7 g of h2o.

Chemistry
1 answer:
Margaret [11]4 years ago
7 0
M(NaCl)=55.84 g
m(H₂O)=157.2 g

m(solution)=m(NaCl)+m(H₂O)

w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/(m(NaCl)+m(H₂O))

w(NaCl)=100*55.84/(55.84+152.7)=26.78%
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Consider the balanced reaction
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Answer:

561 g P₂O₃

Explanation:

To find the mass of P₂O₃, you need to (1) convert moles H₃PO₃ to moles P₂O₃ (via mole-to-mole ratio from equation coefficients) and then (2) convert moles P₂O₃ to grams P₂O₃ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Atomic Mass (P): 30.974 g/mol

Atomic Mass (O): 15.998 g/mol

Molar Mass (P₂O₃): 2(30.974 g/mol) + 3(15.998 g/mol)

Molar Mass (P₂O₃): 109.942 g/mol

1 P₂O₃ + 3 H₂O -----> 2 H₃PO₃

10.2 moles H₃PO₃            1 mole P₂O₃              109.942 g
----------------------------  x  --------------------------  x  -------------------  =  561 g P₂O₃
                                        2 moles H₃PO₃              1 mole

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What is the name for C2H3OH
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Read 2 more answers
Why is scientific notation important in chemistry?
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3 years ago
A helium-filled weather balloon has a volume of 793 L at 16.9°C and 759 mmHg. It is released and rises to an altitude of 4.05 km
mariarad [96]
<h3>Answer:</h3>

1082.96 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of helium gas, V1 = 793 L
  • Initial temperature, T1 = 16.9°C

            But, K = °C + 273.15

  • Thus, initial temperature, T1 is 290.05 K
  • Initial pressure, P1 = 759 mmHg
  • New pressure at 4.05 km, P2 = 537 mmHg
  • New temperature at 4.05 km, T2 = 7.1 °C

                                                             = 280.25 K

Assuming we are required to calculate the new volume at the height of 4.05 km

We are going to use the combined gas law.

  • According to the combined gas law;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

  • Rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(759mmHg)(793L)(280.25K)}{(537mmHg)(290.05K)}

V2=1082.96L

Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L

6 0
3 years ago
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