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RUDIKE [14]
4 years ago
9

Calculate the mass percent (m/m) of a solution prepared by dissolving 55.84 g of nacl in 152.7 g of h2o.

Chemistry
1 answer:
Margaret [11]4 years ago
7 0
M(NaCl)=55.84 g
m(H₂O)=157.2 g

m(solution)=m(NaCl)+m(H₂O)

w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/(m(NaCl)+m(H₂O))

w(NaCl)=100*55.84/(55.84+152.7)=26.78%
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Answer:

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2. How do molecules move in cold water?

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3 0
3 years ago
Concerning the 10.0 mL of 0.50 M NaCl to 100 mL of solution: When a solution is diluted, does it change the number of moles diss
Mars2501 [29]

No, the dilution does not change the number of moles dissolved

Explanation:

We can see that,

The molarity of the solution was 0.50 M

The volume of the solution is 10 ml.

No of moles of the solute was= volume * concentration

                                                   = 10 X 10^-3* 0.50

                                                     = 5*10^-3 moles

When the solution is diluted from 10 ml to 100ml, the molarity or concentration  changes but number of moles remains constant.

The molarity of 100 ml solution will be

c=n/V

  = 5*10^-3*/100*10^-3

  = 0.05

  when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M

8 0
3 years ago
Read 2 more answers
a 15.00 mL sample of an unknown HClO4 solution requires titration with 25.64 mL of 0.2000 M NaOH to reach equivalence point. wha
Veronika [31]

Answer:

V₁ = 0.342 M

Explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M

5 0
3 years ago
When KCl dissolves in water:
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O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).

K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.

that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.

3 0
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Which lists the elements in order from most conductive to least conductive?
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D is the answer. You're welcome...

7 0
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