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Mashcka [7]
3 years ago
5

Determine the amount of energy (heat) in joules required to raise the temperature of 20g of gold from 5°C to 37°C.

Chemistry
1 answer:
insens350 [35]3 years ago
3 0

Answer:

The answer to your question is E = 83.2 J

Explanation:

Data

Element: Gold

Initial temperature = T1 = 5°C

Final temperature = T2 = 37°C

mass = 20 g

Specific heat = 130 J/kg°K

Process

1.- Convert temperature to kelvin

T1 = 273 + 5 = 278°K

T2 = 273 + 37 = 310°K

2.- Convert mass to kg

             1000 g --------------- 1 kg

                 20 g --------------- x

                 x = (20 x 1)/1000

                 x = 0.02 kg

3.- Formula

E = mC(T2 -T1)

4.- Substitution

E = (0.02)(130)(310 - 278)

E = (0.02)(130)(32)

E = 83.2 J

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2 years ago
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nignag [31]

Answer:

3 : 1

Explanation:

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Recall:

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8 0
3 years ago
If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity
olga nikolaevna [1]
<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

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= (10.7g NH4Cl)/(53.5g/mol NH4Cl)

= 0.200 moles NH4Cl  

Then  we convert to liters:

= (800mL)*(1L/1000mL) = 0.800L  

Therefore; molarity = 0.2moles/0.8L

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