Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?
Answer:
The total pressure in the container is 2 atm (Option B)
Explanation:
Step 1: Data given
The initial pressure of the PCl5(g) is 1.00 atm
Volume of the container = 1.00 L
Step 2: The balanced equation
PCl5(g) ⇋ PCl3(g) + Cl2(g)
Step 3: Calculate the total pressure in the container
1mol of ideal gas has a pressure of 1 atm
If 1 mol of PCl5 completely decomposes into 1 mol PCl3 and 1 mol Cl2
Then the pressure for 1 mol PCl3 and 1 mol Cl2 is for both 1 atm
The total pressure would be 2*1 atm = 2 atm
The total pressure in the container is 2 atm
No because he did have a small idea allowing later
more educated scientist in more modern times to review and find mistakes. This
allowed scientist in more modern times to also have develop theories. Every
idea needs fixing and this is one. Since he was first to know about such atoms
and making the "plum pudding model", he gave scientists some thoughts
or possible ideas as to what a substance would be like after its last piece.
