The volume of ideal gas that would occupy at 1.50 atm and 216 c is
2016.49 ml
<u><em>calculation</em></u>
- volume is calculated using a combined gas equation
that is P1V1/T1= P2V2/T2
P1( pressure 1) = 7.20 atm
V1 ( volume 1) = 250 ml
T1 ( temperature 1) = 18 + 273=291 K
P2 ( pressure 2) = 1.50 atm
T2 ( temperature 2)= 216+273=489 K
V2 ( volume 2) =?
- by making V2 the subject of the formula
V2=[(T2 xP1 x V1)/(T1 xP2)]
V2=[ (489 K x 7.20 atm x 250 ml) / ( 291 k x 1.50 atm)] = 2016.49 Ml
Two hydrogens are bonded with nitrogen
Chlorine is bonded with nitrogen
Because nitrogen has 5 valence electrons, and it has only used 3 electrons for bonding with chlorine and hydrogen, there is one pair of electrons left.
3<span> H2SO4
+ 2 Al(OH)3 = Al2(SO4)3
+ 6 H2O</span>
Given :
Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .
Volume of container, V = 28.9 dm³ = 0.0289 m³ .
Pressure, P = 144 kPa = 144000 Pa .
To Find :
Number of moles of nitrogen gas.
Solution :
We know, by ideal gas equation :
PV = nRT ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .
Therefore, number of moles of nitrogen gas is 1.53 moles.