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ratelena [41]
3 years ago
11

Matter and energy are

Chemistry
1 answer:
Wewaii [24]3 years ago
3 0
When energy transforms into mass, the amount of energy does not remain the same. When mass transforms into energy, the amount of energy also does not remain the same. However, the amount of matter and energy remains the same. ... You would weigh much less on the Moon because it is only about one-sixth the mass of Earth. So the answer is D
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The diagram below shows a Bunsen burner heating a beaker of water on a beaker stand. The arrows represent the transfer of heat e
Anna [14]
There's no diagram attached, but diffusion of heat within the water (which i think is what the question's asking) would be due to convection currents.
4 0
3 years ago
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Does ionic or covalent form solid crystals?
Alekssandra [29.7K]

Answer:

I hope it help

your welcome

5 0
3 years ago
Why is sodium hydrogen carbonate an effective antacid but sodium hydroxide is not?
professor190 [17]
Sodium hydrogen carbonate is a weak base, therefore it does not harm the stomach and reduces the stomach acid. Sodium hydroxide is too caustic and not easily buffered and is almost a very strong base. It has a low solubility and dissociation constant, and causes chemical burns in the mouth & throat
8 0
4 years ago
How many moles in 68.1 grams of Cu(OH)2
Andrew [12]

To do this, you would first add together the molar mass of all involved elements, to find how many grams are in a mole of Cu(OH)2. Keep in mind, the molar mass is equal to the atomic mass of an element in grams. For example the molar mass of copper (Cu) would be 63.55 (with 2 sig. figs.)

Therefore, now we add together the mass of all elements involved.

Cu: (63.55)+O2(15.99x2=31.98)+H2(1.01x2=2.02)

63.55+31.98+2.02= 97.55g per mole of Cu(OH)2.

Now, divide what we have by how much it takes to get a mole of the stuff.

68.1/97.55= 0.698mol Cu(OH)2


6 0
3 years ago
What is the energy required to change a spherical drop of water to five smaller spherical drops of equal size? At room temperatu
pav-90 [236]
T<span>his is a straightforward question related to the surface energy of the droplet. </span>

<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>

<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>

<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>

<span>The five smaller droplets need to have the same volume as the original. Therefore </span>

<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>

<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>

<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>

<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>

<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
3 0
3 years ago
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