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Bond [772]
2 years ago
12

The mass of a proton is approximately equal to the mass of…

Chemistry
1 answer:
Misha Larkins [42]2 years ago
5 0

Answer:

1.67262 × 10−27 kg,

Explanation:

I think its right 0_0

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Answer:

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Explanation:

7 0
2 years ago
In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
lawyer [7]
According to the equation you have 1 mole of C2H4 and 3 moles of O2.

1 • (22.4L / 270L) = 3 • (22.4L / x)

1/270L = 3/x

x = 3(270) / 1

x = 810 L

810 Liters of oxygen will react with 270 liters of ethene (C2H4) at STP
4 0
3 years ago
MEASUREMENT AND MATTER Interconverting temperatures in Celsius and Kelvins The metal osmium becomes superconducting at temperatu
nexus9112 [7]

Answer: -272^0C.

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C and K  

These units of temperature are inter convertible.

We are given:

Temperature of the gas = 655mK=0.655K    (1mK=0.001 K)

Converting this unit of temperature into ^0C by using conversion factor:

(t-273.15)^0C=tK

273.15K=0^0C

Thus 0.655K=(0.655-273.15)^0C=-272^0C

Thus the temperature is -272^0C.

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3 years ago
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andriy [413]

Answer:

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7 0
3 years ago
How many grams of phosphorus are required to produce 4.21x10^22 molecules of phosphorus trifluoride?
kolezko [41]

2.1618 grams of P4 is required to produce 4.21x10^22 molecules of phosphorus trifluoride.

Explanation:

The balanced chemical reaction for formation of PF3 from yellow phosphorus is given by:

P4 + 6F2 ⇒ 4PF3

1 mole of P4 reacts to give 4 moles of PF3

It is given that 4.21x10^22 molecules of PF3 are produced

so the number of moles can be calculated by the relation

number of molecules = number of moles × Avagadro number

number of moles = \frac{number of molecules}{avagadro number}

n = \frac{4.21x10^22}{6.023. 10^23}

n= 0.06989 moles of PF3 is formed.

Applying stoichiometry,

1 mole of P4 gives 4 moles PF3

x mole will produce 0.06989 moles of PF3

\frac{4}{1} = \frac{0.0698}{x}

4x= 0.0698 × 1

 x =  \frac{0.0698}{4}

x= 0.01745 moles of P4 will be required.

The weight of the phosphorus can be obtained by number of moles × atomic mass of one mole of P4

= 0.01745 × 123.89

= 2.1618 grams of P4.

     

3 0
3 years ago
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