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Bond [772]
2 years ago
12

The mass of a proton is approximately equal to the mass of…

Chemistry
1 answer:
Misha Larkins [42]2 years ago
5 0

Answer:

1.67262 × 10−27 kg,

Explanation:

I think its right 0_0

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Which of the following is a clue that something is pseudoscience?
adelina 88 [10]
D i think if not here’s this a collection of beliefs or practices mistakenly regarded as being based on scientific method
7 0
3 years ago
In response to action potentials arriving along the transverse tubules, the sarcoplasmic reticulum releasesA) acetylcholine.B) s
stealth61 [152]

Answer:

Calcium ions.

Explanation:

The generation of the action potential helps in the transfer of information to the different body parts. This potential occurs to the difference in membrane potential inside and outside of the cell.

The sarcoplasmic reticulum is the homologous to the endoplasmic reticulum of the cells. The sarcoplasmic reticulum contains calcium ions in it and releases the stored calcium ions on the generation of the action potential. This calcium ion is important for the action of the actin and myosin.

Thus, the correct answer is option (D).

7 0
2 years ago
450 nanometers to meters
lys-0071 [83]

Answer: 4.5 x 10e-7

Explanation: 450 x 1e+9 = correct answer

Multiply amount of nanometers by 1e+9 to get the approximate result in meters.

4 0
3 years ago
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
3 years ago
Plzzz help do your best to answer these questions
vovikov84 [41]

The empirical formula is the simplest formula of a chemical compound.

To find the empirical formula, we take the following steps;

  • Divide the percentage by mass of each element by its relative atomic mass.
  • Divide the quotient of each by the lowest value obtained instep 1 above
  • Write the result of step 2 above as the subscript following each atom.

1) O - 88.10/16,      H - 11.190/1

  O - 5.5,               H - 11.19

  O - 5.5/5.5,        H - 11.19/5.5

  O -  1,                 H - 2

Empirical formula = OH2

2) C - 41.368/12  H - 8.101/1,   N - 32.162/14,   O - 18.369/16

   C - 3,               H - 8,           N - 2,                  O - 1

   C - 3/1,            H - 8/1          N - 2/1                 O - 1/1

    C - 3,             H - 8,           N - 2,                   O - 1

Empirical formula = C3H8N2O

To obtain the molecular formula where n = number of atoms of each element;

Molecular weight = 174.204 g/mol

[ 3(12) + 8(1) + 2(14) + 16]n = 174

n= 174/88

n = 2 (to the nearest whole number)

Hence, we have;

[C3H8N2O]2

The molecular formula is C6H16N4O2

3)  C - 19.999/12,  H - 6.713/1,   N - 46.646/14,   O - 26.641/16

    C - 2,                H - 7,            N -  3,                 O - 2

    C - 2/2,            H - 7/2,         N -   3/2,             O - 2/2

    C - 1,                H - 4,            N -  2,                  O - 1

Empirical formula - CH4N2O

brainly.com/question/1363167

5 0
3 years ago
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