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Bond [772]
2 years ago
12

The mass of a proton is approximately equal to the mass of…

Chemistry
1 answer:
Misha Larkins [42]2 years ago
5 0

Answer:

1.67262 × 10−27 kg,

Explanation:

I think its right 0_0

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Discussion topic
FromTheMoon [43]

Answer: Neither scientist discovered “ Avogadro's number” in the form we use it today (6.02 x 10 23). Still, there's a controversy ...

Explanation: hope this helps

8 0
3 years ago
How many grams are in 4.81 x 10^24 atoms of Li?
stellarik [79]
We are given with a compound, Lithium (Li) having a 4.8x 10 ^24 atoms. We are tasked to solve for it's corresponding grams.Note that 1 mol=6.022x10^{23} atoms and Li has 6.94 g/mol, hence,g Li= 4.8x 10 ^24 atoms x 1 mol/6.022x10^{23} atoms x  6.94 g Li/1mol Li= 
55.32 g

 Therefore, the grams of Lithium is 55.32 g.

3 0
3 years ago
What are valence electrons (be specific)?
Helen [10]
In chemistry, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.
5 0
3 years ago
Read 2 more answers
Sodium bicarbonate undergoes thermal decomposition according to the reaction
geniusboy [140]

Answer: option A, J, K, N, O

Explanation:

7 0
3 years ago
In a reversible chemical reaction at equilibrium, the concentration of X (the reactant) is 0.75 mol/L, and the concentration of
frosja888 [35]

Answer : The value of K_{eq} is, 3

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

X\rightleftharpoons Y

The expression of K_{eq} will be,

K_{eq}=\frac{[Y]}{[X]}

Given:

[X] = 0.75 mol/L

[Y] = 2.25 mol/L

Now put all the given values in the above expression, we get:

K_{eq}=\frac{2.25}{0.75}

K_{eq}=3

Therefore, the value of K_{eq} is, 3

3 0
3 years ago
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