Question

PLEASE HELP AND EXPLAIN!Calculate the energy required to heat 187.0 g of ammonia from 36.1 °C to 52.9 °C. Assume the specific heat capacity of ammonia under these conditions is
4.703.g. K. Round your answer to 3 significant digits.

Answer 1

Answer:

$E=1.48x10^4J$

Explanation:

Hello!

In this case, since the energy implied in a heating process is computed by using the following equation:

$E=mC(T_f-T_i)$

Whereas m is the mass, C the specific heat and T the temperature. In such a way, by plugging in the given mass, specific heat and temperatures, we obtain the following energy:

$E=187.0g*4.703\frac{J}{g\°C} (52.9\°C-36.1\°C)\\\\E=1.48x10^4J$

Considering that the specific heat can by used by unit of °C or K because their difference is equivalent.

Regards!