Answer:
Q = 0.00017597 m3/sec
Explanation:
given data:
temperature of water 15.6 degree celcius
diameter = 10cm =0.1 m
dynamix viscosity of water = .0011193 kg/m sec at 15.6 degree celcius
density of water at 15.6 degree = 999.07 kg/m3
for laminar flow REYNOLD NUMBER < 2000
maximum flow rate =area*velocity
Reynold number 


v = 0.022406 m/sec

where Q is flow expressed in m^3/s

Q =0.00017597 m3/sec
Answer:
<u><em>To answer this question we assumed that the area units and the thickness units are given in inches.</em></u>
The number of atoms of lead required is 1.73x10²³.
Explanation:
To find the number of atoms of lead we need to find first the volume of the plate:

<u>Where</u>:
A: is the surface area = 160
t: is the thickness = 0.002
<u><em>Assuming that the units given above are in inches we proceed to calculate the volume: </em></u>
Now, using the density we can find the mass:

Finally, with the Avogadros number (
) and with the atomic mass (A) we can find the number of atoms (N):
Hence, the number of atoms of lead required is 1.73x10²³.
I hope it helps you!
An algorithm is itself a general step-by-step solution of your problem. ... The most important point here is that you must use algorithms to solve problem, one way or the other. Most of the time it's better to think about your problem before you jump to coding - this phase is often called design.
Answer:
Enter the following code to get the required conditions for the answer.
boston_under_5_height = 1.2
manila_under_5_height = 0.6
boston_5_to_under_10_height = 3.2
manila_5_to_under_10_height = 1.4
boston_under_10 = boston_under_10 = 5*boston_under_5_height + 5*boston_5_to
_under_10_height
manila_under_10 = manila_under_10 = 5*manila_under_5_height + 5*manila_5_to
_under_10_height
Explanation:
Kindly note that question in complete as it belong to the topic of table manipulation and visualization topic. The question asks about the company called Uber and their data extraction from the website called movements.uber.com where data was extracted for 200,000 weekdays in the respective cities of Manila, Philippines and Boston, Massachusetts. Images attached contains the histograms generated for the rides in manila and boston.
Answer:
the relative compaction is 105.88 %
Explanation:
Given;
dry unit weight of field compaction,
= 18 kN/m³
maximum dry unit weight measured,
= 17 kN/m³
Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured
Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

substitute the given values;

RC (%) = 105.88 %
Therefore, the relative compaction is 105.88 %