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White raven [17]
3 years ago
8

How many moles of 2 are required to prepare 2.00 litters of 0.700m CaCl2

Chemistry
1 answer:
bulgar [2K]3 years ago
4 0

Answer:1.4 moles of calcium chloride are required.

Explanation:

Molarity of the calcium chloride solution = 0.700 M = 0.700 mol/L

Volume of the solution = 2 L

Moles of the calcium chloride = x

Molarity=\frac{\text{moles of the substance}}{\text{volume of the Solution (L)}}

0.700 mol/L=\frac{x}{2 L}

x = 1.4 moles of calcium chloride

1.4 moles of calcium chloride are required.

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Vedmedyk [2.9K]
A b A or just the person above me said
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3 years ago
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Solid carbon is known to react with oxygen gas to produce carbon dioxide. If a mass of 1.2g of carbon is burned in oxygen, 4.4g
Elden [556K]

Now ,

C + O2  → CO2

According to above equation, 1 mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.Thus this implies that 12 g of carbon reacts with 32 g of O2 to produce 44 g of CO2.

No of moles = mass of the substance/molecular mass of the substance.

In this case 1.2 g of carbon reacts with "x "g of O2 to produce 4.4 g of CO2.

No of moles of carbon in this case = 1.2÷ 12 = 0.1 moles.

No of moles of carbon dioxide formed = 4.4÷44 =0.1 moles

Thus already discussed above, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. Hence to produce 0.1 mole of CO2 ,0.1 mole of carbon needs to react with 0.1 mole of oxygen.

Also number of moles of O2 = mass of O2÷ molar mass of O2

Substituting number of moles of O2 as 0.1 we get

mass of O2(x)  = Number of moles of O2 × Molar mass of O2

Mass of O2 (x) = 0.1 × 32= 3.2 g

Thus mass of 3.2 g O2 reacts with 1.2 g of CO2 to produce 4.4 g of CO2.



7 0
3 years ago
Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas
nataly862011 [7]

57.1g * 6.022*10^23 / 22.9 * 2 = 7.51*10^23 molecules

3 0
3 years ago
BRAINLIEST IF CORRECT PLEASE USE WORK BONUS POINTS
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the answer is <em>a} physical and chemical changes</em>

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Answer:

b) 1s22s22p63s23p5

Explanation:

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