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OLEGan [10]
3 years ago
12

PLEASE HURRY. Which of the molecules below is propyne?

Chemistry
2 answers:
Oduvanchick [21]3 years ago
7 0

The last photo because its molecular formula is C3H4.

Valentin [98]3 years ago
6 0

Answer: Option (D) is the correct answer.

Explanation:

General formula of an alkyne is C_{n}H_{2n-2}.

Suffix "yne" in the name of a compound represents that there is a triple bond present in the compound.

So, a molecule of propyne will have three carbon atoms, four hydrogen atoms and a triple bond. Therefore, there wll be 6 sigma bonds and 2 pi bonds in a propyne molecule.

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2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea
Alex_Xolod [135]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Moles of HI = 0.550 moles

Volume of container = 2.00 L

\text{Initial concentration of HI}=\frac{0.550}{2}=0.275M

For the given chemical equation:

                          2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>                  0.275

<u>At eqllm:</u>           0.275-2x      x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

K_c=0.0156

Putting values in above expression, we get:

0.0156=\frac{x\times x}{(0.275-2x)^2}\\\\x=-0.0458,0.0275

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.0275 M

Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M

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