When a voltaic cell operates, ions move through a salt bridge. The presence of the salt bridge completes the circuit because it promotes ion flow. It maintains the charges balance since the electron are moving from a half cell to another.
Answer: Heyya, the answer is 0.8539gH2. Pls mark brainliest
Explanation:
Answer:
The value of the carbon bond angles are 109.5 °
Explanation:
CH3CH2CH2OH = propanol . This is an alcohol.
All bonds here are single bonds.
Single bonds are sp³- hybdridization type. To be sp3 hybridized, it has an s orbital and three p orbitals : sp³. This refers to the mixing character of one 2s-orbital and three 2p-orbitals. This will create four hybrid orbitals with similar characteristics.
Sp3- types have angles of 109.5 ° between the carbon - atoms.
This means that the value of the carbon bond angles are 109.5 °
Answer:


Explanation:
Hello,
In this case, given the percent ionization and the concentration of the acid, one computes the concentration of hydrogen ions as follows:
![\% ionization=\frac{[H^+]}{[HA]}*100\%](https://tex.z-dn.net/?f=%5C%25%20ionization%3D%5Cfrac%7B%5BH%5E%2B%5D%7D%7B%5BHA%5D%7D%2A100%5C%25)
![[H^+]=\frac{\% ionization*[HA]}{100\%} =\frac{4\%*0.30M}{100\%}=0.012M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5Cfrac%7B%5C%25%20ionization%2A%5BHA%5D%7D%7B100%5C%25%7D%20%3D%5Cfrac%7B4%5C%25%2A0.30M%7D%7B100%5C%25%7D%3D0.012M)
Therefore the Ka is computed by using the equilibrium expression:
![Ka=\frac{[H^+][A^-]}{[HA]} =\frac{0.012M*0.012M}{0.30M-0.012M}\\ \\Ka=5x10^{-4}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%3D%5Cfrac%7B0.012M%2A0.012M%7D%7B0.30M-0.012M%7D%5C%5C%20%5C%5CKa%3D5x10%5E%7B-4%7D)
And the pH:
![pH=-log([H^+])=-log(0.012)\\\\pH=1.92](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%3D-log%280.012%29%5C%5C%5C%5CpH%3D1.92)
Regards.