1. Who is the father of atomic theory?
Dalton
2. Who discovered the electron?
<span>Thomson
</span>
3. Who expressed particles by wave equations?
<span>Schrödinger
</span>
4. Who researched on radioactivity?
Curie
<span>5. Who discovered the "open spaces" model?
</span><span>Rutherford
</span>
6. Who applied quantum theory to atoms?
<span>Bohr</span>
Answer:
The empirical formula for the compound is C3H4O3
Explanation:
The following data were obtained from the question:
Carbon (C) = 40.92%
Hydrogen (H) = 4.58%
Oxygen (O) = 54.50%
The empirical formula for the compound can be obtained as follow:
C = 40.92%
H = 4.58%
O = 54.50%
Divide by their molar mass
C = 40.92/12 = 3.41
H = 4.58/1 = 4.58
O = 54.50/16 = 3.41
Divide by the smallest i.e 3.41
C = 3.41/3.41 = 1
H = 4.58/3.41 = 1.3
O = 3.41/3.41 = 1
Multiply through by 3 to express in whole number
C = 1 x 3 = 3
H = 1.3 x 3 = 4
O = 1 x 3 = 3
The empirical formula for the compound is C3H4O3
Answer:
C. Refining
Explanation:
Refining process removes elements from a substance
C + 2S → CS2 + 89.3 kJ
Moles of CS2 = 150.0 kJ x (1 mol CS2/89.3 kJ) = 1.680 mol CS2
MW of CS2 = (12.01 + 2x32.06) g/mol = 76.13 g/mol
Mass of CS2 = 1.680 mol CS2 × (76.13 g CS2/1 mol CS2) = 128 g CS2
Answer:
The partial pressure of hydrogen gas at equilibrium is 1.26 atm
Explanation:
Let's use the molar fraction to solve this:
Molar fraction = Moles of gas / Total moles
Molar fraction = Gas pressure / Total pressure
Without equilibrium, we can think that the total system pressure is the sum of the partial pressures of each gas.
1 atm N₂ + 2 atm H₂ = 3 atm
Molar fraction for H₂ = 2 atm / 3atm → 0.66
Let's replace the molar fraction in equilibrium
Gas pressure / 1.9 atm = 0.66
Gas pressure = 1.26atm