To fuel there chemical reactions
Answer:
Examples: Si, B, Ge, Sb, Ga
Explanation:
The majority of elements in the periodic table are classified as either a metal (a species that can lose electrons to become a cation) or a non-metal (a species that can gain electrons to become an anion).
However, there are several atoms which are considered to be metalloids. Metalloids are elements which possess properties that resemble both metals and non-metals. Examples of metalloids would be: silicon (Si), boron (B), germanium (Ge), antimony (Sb), gallium (Ga).
Since metalloids have properties of both metals and non-metals, they are widely used in semiconductors, as they might both donate and accept electrons in their shells.
<span>The
balanced half-reaction: V</span>⁺(aq) → V⁵⁺(aq) + 4e⁻.
Vanadium(I) cations lose four electrons and became vanadium(V) cations.
<span>
Oxidation reaction is increasing of oxidation number of element, because
element or ion lost electrons in chemical reaction.
Reduction is lowering oxidation number because element or ions gain
electrons.</span>
Answer:
0.35 g Li
Explanation:
H2SO4 + 2Li -> Li2SO4 + H2
7 g Li -> 2 g H2
x -> 0.10 g H2
x= (0.10 g H2 * 7 g Li)/ 2 g H2 x= 0.35 g Li
Answer:
<em>C</em> Na+ = 0.228 M
Explanation:
M 2M M
∴ mol Na2S = (0.0478 L)*(0.801 mol/L) = 0.0383 mol
∴V sln = 336.7 mL = 0.3367 L
⇒ <em>C</em> Na2S sln = 0.0383 mol / 0.3367 L = 0.114 M
∴ mol Na+ = (0.0383 mol Na2S)*( 2 mol Na+/ mol Na2S) = 0.0766 mol
⇒ <em>C</em> Na+ = 0.0766 mol / 0.3367 L = 0.2275 M