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3 years ago

Why is it important for scientists to use the scientific method?

Chemistry

2 answers:

lisabon 2012 [21]3 years ago

5 0

Answer:

C. the scientic method helps scientists get accurate,repeatable,results

MakcuM [25]3 years ago

4 0

Explanation:

It provides an objective, standardized approach to conducting experiments and, in doing so, improves their results. By using a standardized approach in their investigations, scientists can feel confident that they will stick to the facts and limit the influence of personal, preconceived notions.

I hope this helps you out!

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What salt is produced in each of the following neutralization reactions?

Pavlova-9 [17]

1. Salt is KNO₃

This is a strong acid - strong base reaction. HNO₃ is the strong acid and KOH is the strong base. 

H⁺ in the HNO₃ and OH⁻ of the KOH pair up and make H₂O(l). 

NO₃⁻ and K⁺ pair up to make KNO₃ salt. 

When writing chemical formulas positive ion comes first and second is negative ion. The charges should be switched. Since positive ion has +1 and negative ion has -1 after the switching off charges the product should be KNO₃.

Balance equation is 
HNO₃(aq) + KOH(aq) → H₂O(l) + KNO₃(aq)

2. Salt is Ca(NO₃)₂

This is a strong acid - strong base reaction. HNO₃ is the strong acid and Ca(OH)₂ is the strong base. 

H⁺ in the HNO₃ and OH⁻ of the Ca(OH)₂ pair up and make H₂O(l). 

Ca²⁺ and NO₃⁻ pair up to make Ca(NO₃)₂ salt. 

Positive ion is Ca²⁺ which has +2 charge and negative ion is NO₃⁻ which has -1 charge. From switching the charges Ca²⁺ gets 1 while NO₃⁻ gets 2. Hence, the salt should be Ca(NO₃)₂.

Balanced equation is
2HNO₃(aq) + Ca(OH)₂(aq) → 2H₂O(l) + Ca(NO₃)₂(aq)

3. Salt is CaCl₂

This is a strong acid - strong base reaction. HCl is the strong acid and Ca(OH)₂ is the strong base. 

H⁺ in the HCl and OH⁻ of the Ca(OH)₂ pair up and make H₂O(l). 

Ca²⁺ and Cl⁻ pair up to make CaCl₂ salt. 

Positive ion is Ca²⁺ which has +2 charge and negative ion is Cl⁻ which has -1 charge. By switching the charges Ca²⁺ gets 1 while NO₃⁻ gets 2. Hence, the salt should be CaCl₂.

Balance equation is
2HCl(aq) + Ca(OH)₂(aq) → 2H₂O(l) + CaCl₂(aq)

4. Salt is KCl

This is a strong acid - strong base reaction. HCl is the strong acid and KOH is the strong base. 

H⁺ in the HCl and OH⁻ of the KOH pair up and make H₂O(l). 

K⁺ and Cl⁻ pair up to make KCl salt. 

Positive ion is K⁺ which has +1 charge and negative ion is Cl⁻ which has -1 charge. By switching the charges K⁺ gets 1 and Cl⁻ also gets 1. Hence, the salt should be KCl.

Balance equation is
HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq)

5 0

3 years ago

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How much heat is required to vaporize 43.9 g of acetone at its boiling point?

bogdanovich [222]

The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below

the heat of vaporization of acetone at its boiling point is 29.1 kj/mole

find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole x 0.757 moles = 22.03 kj

5 0

3 years ago

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I2 is an example of a

Free_Kalibri [48]

Answer:

number

Explanation:

5 0

3 years ago

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rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3, in order o

SVEN [57.7K]

Answer: H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)

Initial important note:

Although NaHCO₃ contents oxygen atoms, and you can calculate its compositoin, the resulting gas does not containg pure oxygen gas (O₂). For the comparisson it is not useful to calculate the content of oxygent atoms, but the concentration of O₂ gas. As such, the gas from NaHCO₃ contains 0% of pure O₂, that is why it is ranked last.

1) Air:

Source: internet

Approximate 23%. It is variable, because air is not a pure substance but a mixture of gases, whose compositon is not unique.

2) Exhaled air:

Source: internet.

Approximate 13%. The compositon of the air changes in our lungs, due to the respiration process: we inhale fresh air with around 23% of oxygen, part of this oxygen pass to the cells (lungs - blood - heart - cells) and then it is exhaled with a lower content of air and a greater content of CO₂

3) Air from the decomposition of H₂O₂.

In this case we can do a chemical calculation, since we can state the chemical equation of the reaction:

i) Chemical Equation:

H₂O₂ (g) → H₂ (g) + O₂ (g)

ii) mole ratio of the products 1 mol H₂ : 1 mol O₂

iii) convert moles into mass (grams)

1 mol H₂ × 2 × 1.008 g/mol = 2.016 g

1 mol O₂ × 2 × 15.999 g/mol = 31.998 g

Composition, % = [31.998 g / (2.016 g + 31.998 g) ] × 100 ≈ 94%

4) Air from the decomposition of NaHCO₃:

i) chemical equation:

2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)

ii) mole ratio: take into account only the gases in the products:

1 mol CO₂ (g) : 1 mol H₂O

iii) mass in grams

CO₂: molar mass ia approximately 44.01 g/mol

H₂O: molar mass is approximately 18.02 g/mol

iii) Those gases although have oxygen atoms, do not hae free oxygen gas, which is what we are compariing. That means, that from the decomposition of NaHCO₃ you get 0% oxygen gas.

5) The result is:

H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)

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3 years ago

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What is the pressure in millimeters of mercury of 0.0130 molmol of helium gas with a volume of 210. mLmL at 55 ∘C∘C? (Hint: You

juin [17]

Answer : The pressure of the helium gas is, 1269.2 mmHg

Explanation :

To calculate the pressure of the gas we are using ideal gas equation:

$PV=nRT$