A dilute acid solution is prepared by adding the concentrated acid to water. If you do the reverse, i.e. add water to the acid it is possible that a small amount water could react with acid and boil and explode thus splashing the acid onto you or someone else near the activity.
Answer:
Explanation:
E = (hc)/(λ)
E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /
(77.8x10^(-9)m)
E = 2.55 x 10^(-11) J
Answer:
V₂ = 0.958 atm
Explanation:
Given data:
Initial volume = 2300 mL (2300/1000 = 2.3 L)
Initial pressure = 1.88 atm
Final volume = (2.21 L + 2.3L) = 4.51 L
Final pressure = ?
Solution;
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.88 atm × 2.3 L = P₂ × 4.51 L
V₂ = 1.88 atm × 2.3 L / 4.51 L
V₂ = 4.32 atm.L / 4.51 L
V₂ = 0.958 atm
Answer:
The coefficient that needs to be placed in front of the products is 2
