Observation of experiment and intervention in newton's optics. newton followed the principle of light through prisms and the rays transmitted through them as a part of his observation. Various properties of light and its characteristics were exposed.
Explanation:
- Newton's investigation of light was based on prisms, lenses and optical rays.
- He stated that lights differing in colour also differed in degrees of re-frangibility.
- To support his theories newton employed "Proof by experiments" method. Each method was designated in revealing a specific property of light.
- A phenomenon known as Newton rings were discovered by newton.
- Newton recognized after pressing together two prisms that there was a transparent spot.
To be honest, I can’t really see the question. So please next time just type it out lol
Answer:
a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.
b) 14.78 grams ammonia is incorporated into 100. g of compound.
Explanation:
a) Ammonium dihydrogen phosphate that is
.
Molecular mass of ammonium dihydrogen phosphate = M
M = 115 g/mol
Percentage of an element in a compound:

Percentage of nitrogen:

Percentage of phosphorus:

b) Percentage of ammonia in 1 molecule of ammonium dihydrogen phosphate.
Molar mass of ammonia = 17 g/mol

Amount of ammonia in 100 grams of compound:
14.78% of 100 g of ammonium dihydrogen phosphate:

14.78 grams ammonia is incorporated into 100. g of compound.
Answer:
Elemental gold to have a Face-centered cubic structure.
Explanation:
From the information given:
Radius of gold = 144 pm
Its density = 19.32 g/cm³
Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:


a = 407 pm
In a unit cell, Volume (V) = a³
V = (407 pm)³
V = 6.74 × 10⁷ pm³
V = 6.74 × 10⁻²³ cm³
Recall that:
Net no. of an atom in an FCC unit cell = 4
Thus;


density d = 19.41 g/cm³
Similarly; For a body-centered cubic structure

where;
r = 144


a = 332.56 pm
In a unit cell, Volume V = a³
V = (332.56 pm)³
V = 3.68 × 10⁷ pm³
V 3.68 × 10⁻²³ cm³
Recall that:
Net no. of atoms in BCC cell = 2
∴


density =17.78 g/cm³
From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.
This makes the elemental gold to have a Face-centered cubic structure.