Use v = vi + at
v = 5.3 m/s + (15 m/s^2)(2.1 s)
v = 5.3 m/s + 31.5 m/s
v = 36.8 m/s
Answer is B
Hope it Helps!
Answer:
This is the midline or the medium which is the exact middle of the graphs minimum and maximum points(which are the amplitude)
M/s2 is the SI of an acceleration.
a couple of things that are necessary to measure this :
- use the timing resources to measure the duty cycle
- performing a computationally intensive division operation
Answer:68.15m/s
Explanation:
<u><em>Given: </em></u>
v₁=15m/s
a=6.5m/s²
v₁=?
x=340m
<u><em>Formula:</em></u>
v₁²=v₁²+2a (x)
<u>Set up:</u>
=
<h2><u><em>
Solution:</em></u></h2><h2><u><em>
68.15m/s</em></u></h2>
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