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stira [4]
3 years ago
7

What would have to be the self-inductance of a solenoid for it to store 10.5 j of energy when a 1.35 a current runs through it?

Physics
1 answer:
Lana71 [14]3 years ago
3 0
It would have to be the right type of metal like copper to run through it
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A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its original wavelength.  The sound wave traveled through a helium balloon (helium is less dense than air could explain this change in wavelength

The pattern of disruption brought on by energy moving away from the sound source is known as a sound wave. Longitudinal waves are what makeup sound. This indicates that the direction of energy wave propagation and particle vibrational propagation are parallel. The atoms oscillate when they are put into vibration.

A high-pressure and a low-pressure zone are created in the medium as a result of this constant back and forth action. Compressions and rarefactions, respectively, are terms used to describe these high- and low-pressure zones. The sound waves go from one medium to another as a result of these regions being transmitted to the surrounding media.

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What is the motion of the particles in this kind of wave?
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Describe where each subatomic particle is found in an atom.
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A 3 5m container is filled with 900 kg of granite (density of 2400 3 kg m/ ). The rest of the volume is air, with density equal
Elina [12.6K]

Complete question:

A 5-m³ container is filled with 900 kg of granite (density of 2400 kg/m3). The rest of the volume is air, with density equal to 1.15 kg/m³. Find the mass of air and the overall (average) specific volume.

Answer:

The mass of the air is 5.32 kg

The specific volume is 5.52 x 10⁻³ m³/kg

Explanation:

Given;

total volume of the container, V_t = 5 m³

mass of granite, m_g = 900 kg

density of granite, \rho _g = 2,400 kg/m³

density of air, \rho_a = 1.15 kg/m³

The volume of the granite is calculated as;

V_g = \frac{m_g}{ \rho_g}\\\\V_g = \frac{900 \ kg}{2,400 \ kg/m^3} \\\\V_g = 0.375 \ m^3

The volume of air is calculated as;

V_a = V_t - V_g\\\\V_a = 5 \ m^3  \ - \ 0.375 \ m\\\\V_a = 4.625 \ m^3

The mass of the air is calculated as;

m_a = \rho_a \times V_a\\\\m_a = 1.15 \ kg/m^3 \ \times \ 4.625 \ m^3\\\\m_a = 5.32 \ kg

The specific volume is calculated as;

V_{specific} = \frac{V_t}{m_g \ + \ m_a} = \frac{5 \ m^3}{900 \ kg \ + \ 5.32\ kg} = 5.52 \times 10^{-3} \ m^3/kg

4 0
3 years ago
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