Answer:
Hello todays answer should be False i am sorry if i am incorrect-Lucy
Explanation:
Answer:
5.71×10¹⁴ Hz
Explanation:
Applying,
v = λf................. Equation 1
Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency
make f the subject of the equation
f = v/λ............. Equation 2
From the question,
Given: λ = 525 nm = 5.25×10⁻⁷ m,
Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s
Substitute these values into equation 2
f = (3.0×10⁸)/(5.25×10⁻⁷)
f = 5.71×10¹⁴ Hz
Hence the frequency of light is 5.71×10¹⁴ Hz
The complete ionization of KBr into its constituents
is:<span>
<span>KBr (s) --->
K+ (aq) + Br- (aq)</span></span>
<span>
During electrolysis, oxidation takes place at the anode electrode. This means
that an ion is stripped off its electron hence becoming more positive:
<span>2 Br- (aq) --->
Br2 (g) + 2e- </span></span>
We can see that Bromine gas Br2 is evolved at the anode.
<span>
<span>Meanwhile at the cathode, the reduction reaction occurs.
Which means that the electron from the anode electrode is used to make an ion
more negative:
<span>2K+ (aq) + 2e- ---> 2K (s) </span></span>
Hence, through reduction, solid potassium is deposited on the
plate.</span>
Half reactions:
<span>Anode: 2 Br- (aq) --->
Br2 (g) + 2e- </span>
<span>Cathode: 2K+ (aq) + 2e-
---> 2K (s) </span>
Answer:
1 Newton
Explanation:
F=9*10^9*q0q1/r^2]]
F=9*10^9*(q0q1)/ r^2
r=3cm
F=4N
F=9*10^9*(q0q1)/3^2
4=9*10^9*(q0q1)/9
4=10^9 q0q1
q0q1=4/10^9
q0q1=4*10^-9
To calculate the force between the forces at a distance of 6 cm
F=9*10^9*(q0q1)/ r^2
=9*10^9*(4*10^-9)/6^2
=9*10^9*(4*10^-9)/36
=10^9*4*10^-9/4
=10^9*10^-9
=1 Newton
the answer is c I hope this helps