The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
Vertically,
s = 15.4 m
u = 0
a = 9.8 m / s²
15.4 = 0 + ( 1 / 2 * 9.8 * t² )
t² = 3.14
t = 1.77 s
Horizontally,
u = 3.01 m / s
a = 0 ( Since there is no external force )
s = ( 3.01 * 1.77 ) + 0
s = 5.34 m
Therefore, the distance travelled by the ball before hitting the ground is 5.34 m
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 Answer:
Explanation:
The form of Newton's 2nd Law that we use for this is:
F - f = ma where F is the Force pulling the mass down the ramp forward, f is the friction trying to keep it from moving forward, m is the mass and a is the acceleration (and our unknown).
We know mass and we can find f, but we don't have F. But we can solve for that by rewriting our main equation to reflect F:
 That's everything we need.
 That's everything we need. 
w is weight: 6.0(9.8). Filling in:
6.0(9.8)sin20 - .15(6.0)(9.8) = 6.0a and
2.0 × 10¹ - 8.8 = 6.0a and
11 = 6.0a so
a = 1.8 m/s/s
 
        
             
        
        
        
To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as


PART A ) 


Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 




Now calculate the angular velocity of the motorcycle



Calculate the angular acceleration of the motorcycle



Calculate the time needed by the motorcycle to reach an acceleration of 




PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 




PART C) 
Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is 



Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is 



PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is 




 
        
             
        
        
        
Answer:
196000 N
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Area (A) = 2 m²
Force (F) =.? 
Next, we shall determine the pressure in the tank. 
This can be obtained as follow:
P = dgh
Where 
P is the pressure.
d is the density of the liquid. 
g is acceleration due to gravity 
h is the height. 
Height (h) = 10 m
Density (d) of water = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Pressure (P) =...? 
P = dgh
P = 1000 × 9.8 × 10
P = 98000 N/m²
Therefore, the pressure acting on the tank is 98000 N/m²
Finally, we shall determine the force of gravity acting on the column of water as follow:
Area (A) = 2 m²
Pressure (P) = 98000 N/m²
Force (F) =.?
Pressure (P) = Force (F) /Area (A) 
P = F /A
98000 = F/ 2
Cross multiply 
F = 98000 × 2
F = 196000 N
Therefore, the force of gravity acting on the column of water is 196000 N
 
        
                    
             
        
        
        
Answer:9m
Explanation:
Ball starts from rest . Time taken = 6 seconds. Distance travelled by ball. ∴Distance travelled = 9 m
Hope it helps you 
Good luck