Answer: Transverse
Explanation: Transverse waves possess a vertical wave motion and a horizontal particle motion.
Answer: a=-2.4525 m/s^2
d=s=190.3 m
Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr
Fr = 25% of weight
W=mg
W=1750*9.81
W=17167.5
Hence

Frictional force is negative as it acts in opposite direction
According to newton second law of motion
F=ma
hence


given
u= 110 km/h
u=110*1000/3600
u=30.55 m/s
to get t we know that final velocity v=0

Explanation:
Given that,
Mass of the car, m₁ = 1250 kg
Initial speed of the car, u₁ = 7.39 m/s
Mass of the truck, m₂ = 5380 kg
It is stationary, u₂ = 0
Final speed of the truck, v₂ = 2.3 m/s
Let v₁ is the final velocity of the car. Using the conservation of momentum as :



So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.