If T, = 40 N, find T, and the mass of the weight (W).

Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p

boyakko [2]

Answer:

The number of free electrons per cubic meter is $7.61\times 10^{28}\ m^{-3}$

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, $\sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}$

Density of metal, $\rho=10.5\ g/cm^3$

Atomic weight, A = 107.87 g/mol

Let n is the number of free electrons per cubic meter such that,

$n=1.3\ N$

$n=1.3(\dfrac{\rho N_A}{A})$

Where

$\rho$ is the density of silver atom

$N_A$ is the Avogadro number

A is the atomic weight of silver

$n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})$

$n=7.61\times 10^{22}\ cm^{-3}$

or

$n=7.61\times 10^{28}\ m^{-3}$

Hence, this is the required solution.

6 0

3 years ago

1) Consider a source particle of charge qS=9 C located at (−9,5) [distances in meters]. Find the electric field vector at the ta

xeze [42]

Answer:

1) E = 2.25 i^+ 0.809j^) 10⁹ N / C , 2) E = 2.39 10⁹ N / C , 3) θ = 19.8º , 4) F = 19.12 10⁹ N , 5) E = (1.32 i^+ 3.56 j^) 109 N/C

Explanation:

1) The equation for the electric field is

E = k q / r²

Where K is the Coulomb constant that is worth 8.99 10⁹ N m² /C², q is the load and r is the distance of the load to the test point

Since the electric field is a vector magnitude, we can find its component

X axis

Ex = k q / x²

where the distance on the axis is

x = √ (X₂-x₁)²

x = √ (-15 + 9)² = 6 m

Eₓ = 8.99 10⁹ 9/6²

Eₓ = 2.25 10⁹ N /C

Y Axis

y = √ (y₂-y₁)² = √ (15-5)² = 10 m

$E_{y}$ = 8.99 10⁹ 9/10²

$E_{y}$ = 0.809 10⁹ N / C

E = Eₓ i^+ $E_{y}$ j^

E = 2.25 i^+ 0.809j^) 10⁹ N / C

2) the magnitude can be found using the Pythagorean triangle

E = √ (Eₓ² + $E_{y}$ ²)

E = √ (2.25² + 0.809²) 10⁹

E = 2.39 10⁹ N / C

3) to find the angle let's use trigonometry

tan θ = $E_{y}$ / Eₓ

θ = tan⁻¹ $E_{y}$ / Eₓ

θ = tan⁻¹ (0.809 / 2.25)

θ = 19.8º

Regarding the positive side of the x axis

4) a charge q2 = 8C is placed, let's calculate the force

F = q E

F = 8 2.39 10⁹

F = 19.12 10⁹ N

5) The total electric field at the origin, let's look for its components

q₁ = 9C

r₁ = -9 i ^ + 5 j ^

q₂ = 8 C

r₂ = -15 i ^ + 15 j ^

X axis

Eₓ = E₁ₓ + E₂ₓ

Eₓ = k q₁ / Dx₁² + k q₂ / Dx₂²

Eₓ = 8.99 10⁹ (9 / (9-0)² + 8 / (15-0)²)

Eₓ = 1.32 109 N / A

Y Axis

$E_{y}$ = $E_{1y}$ + $E_{2y}$

$E_{y}$ = k q₁ / Δy₁² + k q₂ / Δy₂²

$E_{y}$ = 8.99 109 (9/5² + 8/15²)

$E_{y}$ = 3.56 109 N / A

E = (1.32 i^+ 3.56 j^) 109 N/C

7 0

4 years ago

Who invented the assembly line what purpose does it serve

insens350 [35]

Answer:

Ransom E. Olds was the person who invented assembly line.

The assembly line method was the very first method to be used in automotive sector and was the prototype for which Henry Ford industries had developed his own.

Explanation:

Ransom E. Olds was the person who invented assembly line.

The assembly line method was the very first method to be used in automotive sector and was the prototype for which Henry Ford industries had developed his own. Henry Ford enhanced the design of assembly line through the use of a conveyor system's running platforms.

The assembly line has always been recognized as among the 20th century's greatest inventions. It so profoundly influenced the industrialized world that industries that didn't adopt the trend quickly became extinct and was one of the primary factors that helped to incorporate the automobile into American society.

6 0

3 years ago

At what time of day would you expect the New Moon to rise?

abruzzese [7]

Answer:

At what time of day would you expect the New Moon to rise?

A) Midnight

B) Sunset

C) Noon

D) Sunrise

An HR diagram is a plot of:

A) Luminosity versus apparent magnitude.

B) Absolute magnitude versus luminosity.

C) Absolute magnitude versus surface temperature.

D)Apparent magnitude versus color index.

E) Color index versus surface temperature.

What is the most easily visible manifestation of the Earth's magnetic field?

A) The Van Allen radiation belts

B) The magnetopause

C) The aurorae

D) There is no easily visible manifestation of the Earth's magnetic field.

For a lunar eclipse (the moon is obscured from view), which phase is necessary?

A) third quarter

B) new moon

C) first quarter

D) full moon

4 0

3 years ago

Select the correct statement about the flow of power as a function of time between a balanced three-phase source and a balanced

Akimi4 [234]

Answer:

Total power flow in a balanced system is constant with time

Therefore, the torque required to a balance load is constant and the vibration is lessened

Explanation:

3 0

3 years ago