Answer:
A
Explanation:
Force of gravity can be expressed as:
F = GMM/R^2
Where
F = gravitational force
M = mass
R = distance
Also, W = mg
From the above equation, we can deduce that force of gravity actually depends on mass and not volume.
The correct answer is therefore A.
Had twice as much mass
Therefore, the force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your school would be exactly twice as much if your school Had twice as much mass
Answer:
2.461
Explanation:
Let mass of Bonzo = m1
Mass of Ender =m2
When they push eachother from stationary position
Initial velocity of Bonzo = Vib=0 m/s
Final velocity of Bonzo = Vfb= 1.3 m/s
Initial velocity of Ender = Vie= 0 m/s
Final velocity of Ender = Vfe= -3.1 m/s
We know initial momentum = final momentum
==> m1Vib+m2Vie = m1Vfb+m2Vfe
==> 0+0= m1×1.3 +m2×(-3.1)
==> 1.3m1-3.1m2=0
==> 1.3 m1 = 3.2 m2
==> m1/m2 = 3.2/1.3
==> m1/m2 = 2.461
The polarized glasses contain a special filter that blocks the glares and the hazes while driving through the sun or looking at the water, which makes your eyes more comfortable and makes you see better.
Hope this Helps! :)
Answer:
a) 9.99 s
b) 538 m
c) 20.5 s
d) 1160 m
Explanation:
Given:
x₀ = 0 m
y₀ = 49.0 m
v₀ = 113 m/s
θ = 60.0°
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
a) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find t.
vᵧ = aᵧ t + v₀ᵧ
(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)
t ≈ 9.99 s
b) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find y.
vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)
(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)
y ≈ 538 m
c) When the projectile lands, y = 0 m. Find t.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²
You'll need to solve using quadratic formula:
t ≈ -0.489, 20.5
Since negative time doesn't apply here, t ≈ 20.5 s.
d) When the projectile lands, y = 0 m. Find x. (Use answer from part c).
x = x₀ + v₀ₓ t + ½ aₓ t²
x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²
x ≈ 1160 m
When a mass of 8 kg is located on the Earth's surface, the magnitude of each of
the gravitational forces attracting the mass and the Earth toward each other is
(mass) x (acceleration of gravity on Earth) =
(8.0 kg) x (9.81 m/s²) =
78.48 kg-m/s² = <em>78.48 newtons </em>(about 17 pounds 10.2 ounces)
