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lord [1]
4 years ago
8

You know the deal kingdom

Chemistry
1 answer:
SVETLANKA909090 [29]4 years ago
7 0

Answer:

D. protons that is the answer

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What would happen if I removed a resistor from a parallel circuit? What would
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In a parallel circuit, current divides through resistors and current might be different depending upon the resistor and all resistors have the same potential difference. Therefore, if a parallel resistor was removed then the total resistance of the circuit will increase.

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MgS is the chemical formula for the ionic compound named
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Magnesium Chloride

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*WILL GIVE BRAINLIEST TO CORRECT ANSWER*<br> Question in picture**
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D

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can anyone explain to me how to balance a chemical equation? im having trouble in understanding how i keep getting it wrong.
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For example we are going to use this unbalanced chemical reaction:
H₂ + O₂ → H₂O.
First, calculate number of atoms (hydrogens and oxygens) on left and right. There is two oxygen and two hydrogen on left and two hydrogen and one oxygen on right.
You can not change molecular formula of compound, only you can put coefficient in fron of compound to balance reaction.
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3 years ago
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of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measu
krok68 [10]

The question is incomplete . The complete question is :

100 mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.107atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits.

Answer:  The molar mass of the protein is 4.57\times 10^3g/mol

Explanation:

\pi =CRT

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 0.107 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (protein) = 100 mg = 0.1 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

0.107=1\times \frac{0.1\times 1000}{\text{Molar mass of insulin}\times 5.00}\times 0.0821\text{ Latm }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of protein}

\text{molar mass of protein}=4.57\times 10^3g/mol

Hence, the molar mass of the protein is 4.57\times 10^3g/mol

7 0
3 years ago
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