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Sloan [31]
3 years ago
8

How does the fission of uranium-235 produce a chain reaction?

Chemistry
1 answer:
Helga [31]3 years ago
3 0
If an least one neutron from U-235 fission<span> strikes another nucleus and causes it to fission, then the chain reaction will continue. If the reaction will sustain itself, it is said to be "critical", and the mass of U-235 required to produced the critical condition is said to be a "</span>critical mass<span>". A critical chain reaction can be achieved at low concentrations of U-235 if the neutrons from fission are </span>moderated<span> to lower their speed, since the probability for fission with slow neutrons is greater.  Hope that helps ya.</span>
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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

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sammy [17]

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3 0
2 years ago
A helium balloon has a volume of 2.00L at 101kpa. As the balloon rises the pressure drops to 97.0kPa. What is the new volume?
Mrrafil [7]

Answer:

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V2 = 202/97 = 2.08L

Therefore, the new volume is 2.08L

4 0
3 years ago
Read 2 more answers
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