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Sloan [31]
3 years ago
8

How does the fission of uranium-235 produce a chain reaction?

Chemistry
1 answer:
Helga [31]3 years ago
3 0
If an least one neutron from U-235 fission<span> strikes another nucleus and causes it to fission, then the chain reaction will continue. If the reaction will sustain itself, it is said to be "critical", and the mass of U-235 required to produced the critical condition is said to be a "</span>critical mass<span>". A critical chain reaction can be achieved at low concentrations of U-235 if the neutrons from fission are </span>moderated<span> to lower their speed, since the probability for fission with slow neutrons is greater.  Hope that helps ya.</span>
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If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?
Semenov [28]

Answer:

see explanation below

Explanation:

The question is incomplete. Here's the complete question:

<em>Consider the following reaction: </em>

<em>SO2Cl2 -----> SO2(g) + Cl2(g) </em>

<em>Kc= 2.99 x 10^-7 at 227 degrees celcius </em>

<em>If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?</em>

This is a problem of equilibrium, therefore, we need to solve this using the expression of equilibrium constant. To do that, we need to wirte an ICE chart and solve from there:

       SOCl2 ---------> SO2 + Cl2     Kc = 2.99x10⁻⁷

i)       0.168                  0        0

c)         -x                    +x       +x

e)     0.168-x                x         x

Writting the Kc expression:

Kc = [SO2] [Cl2] / [SOCl2]

Replacing the values from the chart:

2.99x10⁻⁷ = x² / 0.168 - x

However, Kc is a very very small value, therefore, we can assume that the value of "x" would be very small too, and we can neglect the 0.168-x and just round it to 0.168:

2.99x10⁻⁷ = x²/0.168

2.99x10⁻⁷ * 0.168 = x²

√5.02x10⁻⁸ = x

x = 2.24x10⁻⁴ M

This means then, that the concentration of Cl2 in equilibrium would be:

<em>[Cl₂] = 2.24x10⁻⁴ M</em>

5 0
3 years ago
In a pure metal, the electrons can be thought of as [ Select ] throughout the metal. Using molecular orbital theory, there [ Sel
Phoenix [80]

Answer:

Explanation:

In a pure metal, the electrons can be thought of as [concentrated] around atoms throughout the metal. Using molecular orbital theory, there [is ] an energy gap between the filled molecular orbitals and empty molecular orbitals. The [antibonding] orbitals are typically higher in energy and are mostly (filled]

5 0
3 years ago
Plz help me with these three please please !!!!!
Novay_Z [31]

Explanation:

Cations are positively charged ions with fewer electrons than protons. To partake in reaction, metals lose electrons to achieve a stable octet configuration. It has lost valence electrons and wold have a positive charge associated with it.

Potassium is a group 1 element. A metal.

Potassium has 1 valence electron so it loses the valence electron to form a stable octet.

A potassium ion has a positive charge and therefore cannot be an anion but is a cation.

The group number pretty much denotes the number of valence electrons.

Group 1 = 1

Group 2 = 2

Group 17 = 7

Group 18 = 8

4 0
3 years ago
3. 2.15 x 3.1 x 100 =
jeka94

Answer:

666.5

Explanation:

Multiply 2.15 and 3.1 to get 6.665.

6.665×100≈666.5

Multiply 6.665 and 100 to get 666.5.

666.5

3 0
3 years ago
Read 2 more answers
A sample of an unknown gas at STP has a density of 0.630 gram per liter. What is the gram molecular mass of this gas?
jeyben [28]
<span>STP means standard temperature and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the numer of moles and can be represented as mass of the gas, m, divided by the molar mass, c.  so we have,</span>  

PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P  

substitute the values into the equation,
c = [(0.63g/L)(0.08206 L-atm/mol-K)(273K)]/(1atm)
<u>c = 14.11 g/mol</u>
3 0
3 years ago
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