Answer:
The final speed of the two carts is 1 m/s.
Explanation:
let m = 0.5 kg being the mass of the cart moving at an intial speed of v = 4 m/s and M = 1.5 kg is the mass of the cart at rest V = 0 m/s.
then by conservation of linear momentum, the final speed of the objects Vf is:
m×v + M×V = Vf×(M + m)
Vf = [m×v + M×V]/(M + m)
Vf = [(0.5 kg)×(4 m/s) + (1.5 kg)×(0 m/s)]/(1.5 + 0.5 kg)
= 1 m/s
Therefore, the final speed of the two carts is 1 m/s.
Answer:
10 seconds
Explanation:
We can calculate the average speed by finding the total distance traveled divided by the elapsed time: Average speed=–s=Total distance Elapsed time
The car will take 300 m before it stops due to applying break.
<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
- Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
- So, 0² - 60² = 2×6× S
=> -3600 = -12S
=> S = 3600/12 = 300 m
Thus, we can conclude that the distance covered by the car is 300 m before it stopped.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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Answer:
B. Our technology has not advanced enough to make faster-than-light travel possible
Explanation:
So far, we don't know of anything that can go faster then the speed of light.