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Anit [1.1K]
3 years ago
7

Which by freud domain would cover bullying

Physics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

Bias-based bullying among youth increases when controversial voter referendums (e.g., marriage equality) arouse divisive political discourse and receive

Explanation:

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What force is necessary to keep a mass of 0.8 kg revolving in a horizontal circle of radius 0.7 m with a period of 0.5 s? What i
inn [45]

Answer:

88.34 N directed towards the center of the circle

Explanation:

Applying,

F = mv²/r................... Equation 1

F = Force needed to keep the mass in a circle, m = mass of the mass, v = velocity of the mass, r = radius of the circle.

But,

v = 2πr/t................... Equation 2

Where t = time, π = pie

Substitute equation 2 into equation 1

F = m(2πr/t)²/r

F = 4π²r²m/t²r

F = 4π²rm/t²............. Equation 3

From the question,

Given: m = 0.8 kg, r = 0.7 m, t = 0.5 s

Constant: π = 3.14

Substitute these values into equation 3

F = 4(3.14²)(0.7)(0.8)/0.5²

F = 88.34 N directed towards the center of the circle

8 0
3 years ago
A boy and his skateboard have a combined mass of 65 kg. What is the speed of the boy and skateboard if they have a momentum of 2
Yanka [14]
4.2m/s. Momentum=mass x velocity so 275/65=velocity=4.23
3 0
3 years ago
Read 2 more answers
3. With a<br> you can measure just about anything.
Degger [83]
MULTIMETER combines the functions of ammeter, voltmeter and ohmmeter as a minimum.
5 0
3 years ago
Aunt Jane weights 45 Newtons. What is her mass?
RUDIKE [14]

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

8 0
3 years ago
Old-fashioned pendulum clocks are powered by masses that need to be wound back to the top of the clock about once a week to coun
Andreyy89

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, m_1=4\ kg

Mass 2, m_2=4\ kg

Mass 3, m_3=6\ kg

Height from which they are dropped, h = 1.3 m

Let m is the energy used by the clock in a week. The energy is equal to the gravitational potential energy. It is given by :

E=(m_1+m_2+m_3)gh

E=(4+4+6)\times 9.8\times 1.3

E = 178.36 J

So, the energy used by the clock in a week is 178.36 Joules. Hence, this is the required solution.

6 0
3 years ago
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