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jekas [21]
3 years ago
10

A body of mass 1kg is made to oscillate on a spring of force constant 16 n/m calculate 1 the angular frequency 2 the frequency o

f oscillation
​
Physics
1 answer:
Scilla [17]3 years ago
7 0

Explanation:

Given that,

Mass of a body, m = 1 kg

Force constant, k = 16 N/m

We need to find the angular frequency and the frequency of oscillation.

(a) The angular frequency of a body is given by :

\omega=\sqrt{\dfrac{k}{m}} \\\\=\omega=\sqrt{\dfrac{16}{1}} \\\\=4\ rad/s

(b) The frequency of oscillation is given by :

f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\=\dfrac{2}{\pi}\ Hz

Hence, this is the required solution.

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nevsk [136]

Answer: <em>Around each new moon and full moon, the sun, Earth, and moon arrange themselves more or less along a line in space. Then the pull on the tides increases, because the gravity of the sun reinforces the moon's gravity. ... This is the spring tide: the highest (and lowest) tide. Spring tides are not named for the season.</em>

8 0
3 years ago
What speed would a fly with a mass of 0.72 g need in order to have the same kinetic energy as a 1250 kg automobile traveling at
Elena L [17]
Kinetic of automobile

Mass m = 1,250 Kg;         V = 11 m/s

Formula: K.E = 1/2 mV²

               K.E = 1/2(1,250 Kg)(11 m/s)²

               K.E = 75,625 J

Speed required for insect to have the same kinetic energy as automobile

Mass of insect = 0.72 g convert to Kg   m = 7.2 x 10⁻⁴ Kg

K.E = 1/2 mV²  Derive V =?

 V = 2 K.E/m

 V = √2(75,625 J)/7.2 x 10⁻4 Kg

 V = √2.1 x 10⁸ m²/s²

 V = 14,491.34 m/s  (velocity of insect)









5 0
3 years ago
Two blocks of masses 1 = 700 and 2 = 1100 are connected by a cord of negligible mass and hung over a diskshaped pulley, as shown
ivanzaharov [21]

Answer:

b) 16 cm

Magnification, m = v/u

3 = v/u

⇒ v = 3u

Lens formula : 1/v – 1/u = 1/f

1/3u = 1/u = 1/12

-2/3u = 1/12

⇒ u = -8 cm

V = 3 × (-8) = -24

Distance between object and image = u – v = -8 – (-24) = -8 + 24 = 16 cm

Explanation:

3 0
3 years ago
At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (7.00 m/s2)i hat + (6.00 m/s2)j. It m
Elina [12.6K]

Answer:

r = 3519.55 m

Explanation:

We know that the acceleration of a particle in a circular motion is directed towards the center of the circumference and has magnitude:

F = rω^2

Where r is the radius of the circumference and ω is the angular velocity.

From the two acceleration vectors we find that their magnitude is

√(7^2+6^2) = √85

Therefore:

√85 m/s^2= rω^2

Now we need to calculate the angular velocity to obtain the radius. Since t2-t1 = 3s is less than one period we can be sure that the angular velocity is equals to the angle traveled between this time divided by 3 s.

The angle with respect to the x-axis  for the particle at t1 and t2 is:

\theta 1 =\cos ^{-1}\left(\frac{7}{\sqrt{85}}\right)\\\theta 2 =\cos ^{-1}\left(\frac{6}{\sqrt{85}}\right)\\

Therefore, the angular velocity ω is (in radians per second):

\omega = \frac{\theta2 - \theta1}{3 s} = 0.0511813 \frac{1}{s}

Therefore:

r = √85 / (0.0511813)^2 = 3519.55 m

4 0
3 years ago
Which molecules are in put in photosynthesis
Dmitry_Shevchenko [17]

Answer:

During the process of photosynthesis, cells use carbon dioxide and energy from the Sun to make sugar molecules and oxygen. These sugar molecules are the basis for more complex molecules made by the photosynthetic cell, such as glucose.

Explanation:

yes.

6 0
2 years ago
Read 2 more answers
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