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morpeh [17]
3 years ago
6

In asparagine, determine the maximum number of hydrogen bonds that each o, n , or h atom can make to a water molecule. (consider

any intermolecular attractions between the asparagine molecule and water to be hydrogen bonds.)
a. the uncharged oxygen atoms can make up to ... hydrogen bond(s).
b.The negatively charged oxygen atom can make up to ... hydrogen bond(s)
c.The uncharged nitrogen atom can make up to ... hydrogen bond(s)
d. The positively charged nitrogen atom can make up to ... hydrogen bondse) each hydrogen atom can make up to ... hydrogen bond(s)
Chemistry
1 answer:
Mkey [24]3 years ago
8 0
A Hydrogen bond will stablish between the protons of the water and the free electron pairs of the electronegative atoms on asparagine, so:

a) can make up to 2 hydrogen bonds, since it has 2 free electron pairs.

b) can make up to 3 hydrogen bonds, since the negative charge makes up for 1 free electron pair aditional to the 2 oxygen already has.

c) can make up to 1 hydrogen bond, since it has 1 free electron pair.

d) since they have no free electron pairs, they cannot establish hydrogen bonds.
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Now molecules: Choose... molecules of H 2 + Choose... molecules of O 2 → Choose... molecules of H 2 O
kirill [66]
Consider this balanced chemical equation:
2 H2 + O2 → 2 H2O
We interpret this as “two molecules of hydrogen react with one molecule of oxygen to make two molecules of water.” The chemical equation is balanced as long as the coefficients are in the ratio 2:1:2. For instance, this chemical equation is also balanced:
100 H2 + 50 O2 → 100 H2O
This equation is not conventional—because convention says that we use the lowest ratio of coefficients—but it is balanced. So is this chemical equation:
5,000 H2 + 2,500 O2 → 5,000 H2O
Again, this is not conventional, but it is still balanced. Suppose we use a much larger number:
12.044 × 1023 H2 + 6.022 × 1023 O2 → 12.044 × 1023 H2O
These coefficients are also in the ratio of 2:1:2. But these numbers are related to the number of things in a mole: the first and last numbers are two times Avogadro’s number, while the second number is Avogadro’s number. That means that the first and last numbers represent 2 mol, while the middle number is just 1 mol. Well, why not just use the number of moles in balancing the chemical equation?
2 H2 + O2 → 2 H2O
6 0
3 years ago
Why is melting point considered a physical property
miskamm [114]

Answer:

Because you can physically see the object melting when it comes to the melting point. The objects texture, color, temperature, shape, and state of matter (solid, liquid, gas) are possibly changing.

6 0
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A runner competed in a 5-mile run. How many yards did she run?
vfiekz [6]
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so b. is the correct answer. plz like and hope it helped
3 0
3 years ago
An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t
topjm [15]

Answer:

\boxed{3}

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}

Data:

n_{f} = 2

λ = 657 nm

Calculation:  

\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

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Answer:

The main function of the cell membrane is to protect the cell from the outer environment.

8 0
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