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sesenic [268]
3 years ago
10

Does water take a long time to lose heat compared to metal? what is this called

Physics
2 answers:
Mariulka [41]3 years ago
6 0

Explanation:

It is called thermodynamics which is based on specific heat capacity of the substance

Finger [1]3 years ago
5 0

Answer:

The correct answer is

Explanation:

Yes, water takes a longer time to lose heat compared to metal because water heats up faster than metal. The process is called thermodynamics or can also be called evaporation.

Hope this helps....

Have a nice day!!!!

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Find the specific gravity of the rose quartz. Specific gravity = density of of water.
Veronika [31]
It has no units. not sure.
6 0
3 years ago
A ball thrown straight up into the air is found to be moving at 6.79 m/s after falling 1.87 m below its release point. Find the
MaRussiya [10]

Answer:

3.07 m/s

Explanation:

We know that from kinematics equation

v^{2}=u^{2}+2as and here, a=g where v is the final velocity, u is the initial velocity, a is acceleration, s is the distance moved, g is acceleration due to gravity

Making u the subject then

u=\sqrt {v^{2}-2gs}

Substituting v for 6.79 m/s, s for 1.87 m and g as 9.81 m/s2 then

u=\sqrt {6.79^{2}-(2\times 9.81\times 1.87)}=3.068338313 m/s\approx 3.07 m/s

5 0
3 years ago
- A thin film of oil * (n = 1.45) on a puddle of water, producing different colors. What is the minimum thickness of a place whe
Darya [45]

Answer:

There will be a phase change at the first interface and no phase change at the second interface:

If the film is 1/4 wavelength thick this restriction will hold

The wavelength of the light in oil is 545 nm / 1.45 = 376 nm

376 nm / 4 = 94 nm

"D" is correct

4 0
3 years ago
By counting the number of crests that pass in a given amount of time, a person can calculate the
ladessa [460]
By calculating the crests, you can find the waves' frequency.
Hope this helps!
3 0
3 years ago
The current in a coil with a self-inductance of 1 mH is 2.8 A at t = 0, when the coil is shorted through a resistor. The total r
pogonyaev

Given:

L = 1 mH = 1\times 10^{-3} H

total Resistance, R = 11 \Omega

current at t = 0 s,

I_{o} = 2.8 A

Formula used:

I = I_{o}\times e^-{\frac{R}{L}t}

Solution:

Using the given formula:

current after t = 0.5 ms = 0.5\times 10^{-3} s

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I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}

I =   2.8\times e^-5.5

I =0.011 A

5 0
3 years ago
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