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Sever21 [200]
3 years ago
7

An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, (a) the tem

perature of the gas remains constant and the pressure decreases. (b) both the temperature and pressure of the gas decrease. (c) the temperature of the gas decreases and the pressure increases. (d) both the temperature and volume of the gas increase. (e) both the temperature and pressure of the gas increase. Group of answer choices a b c d e
Physics
1 answer:
Ivan3 years ago
6 0

Answer:

(b) both the temperature and pressure of the gas decrease.

Explanation:

An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.

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A 75-hp (shaft output) motor that has an efficiency of 91% is worn out and is replaced by a high efficiency 75-hp motor that has
ZanzabumX [31]

Answer:

The heat gain of the room due to higher efficiency is 2.84 kW.

Explanation:

Given that,

Output power of shaft = 75 hp

Efficiency = 91%

High efficiency = 95.4%

We need to calculate the electric input given to motor

Using formula of efficiency

\eta=\dfrac{Work\ Output}{Work\ input}

Work\ Input =\dfrac{Work\ output}{\eta}

Work\ Input =\dfrac{75\times746}{0.91}

Work\ Input =61483.51\ W

Work\ Input = 61.48 kW

We need to calculate the electric input

For, heigh efficiency

Work\ Input_{inc} =\dfrac{75\times746}{0.954}

Work\ Input_{int} =58647.7\ W

Work\ Input_{int} = 58.64\ kW

The reduction of the heat gain of the room due to higher efficiency is

Q=Work\ Input-Work\ Input_{int}

Put the value into the formula

Q=61.48 -58.64

Q=2.84\ kW

Hence, The heat gain of the room due to higher efficiency is 2.84 kW.

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The constellation Canis Minor has a binary star system consisting of Procyon A and Procyon B. Procyon A, at 3×1030kg, has 2.5 ti
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This question involves the concepts of Newton's Law of Gravitation and mass.

The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".

Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:

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m₁ = mass of Procyon A = 3 x 10³⁰ kg

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r = distance between them = 2 x 10¹² m

Therefore,

F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3\ x\ 10^{30}\ kg)(7.5\ x\ 10^{30}\ kg)}{(2\ x\ 10^{12}\ m)^2}

<u>F = 3.75 x 10²⁶ N</u>

Learn more about Newton's Law of Gravitation here:

brainly.com/question/17931361?referrer=searchResults

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