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mihalych1998 [28]
3 years ago
7

During the 28-day lunar cycle, the positions of the Sun,

Physics
1 answer:
Mnenie [13.5K]3 years ago
8 0
The answer is full moon because that’s how it changes in life
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Difference between Pascal’s law and law of flotation
irakobra [83]
Hi, I didn’t understand too well your question, but I hope this helps!


Archimedes principle is based on the weight of the object to push the object upward. ​Law of floation is the priciple which tells us about the density of the object with the liquid in which it is placed.
5 0
2 years ago
The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
Novay_Z [31]

Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec

4 0
3 years ago
Which material will heat up the most quickly if placed near a heat source?
Thepotemich [5.8K]

Answer:

Metal

Explanation:

Just answered on Apex

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP! IS MY ANSWER CORRECT?
Flura [38]
No. The correct answer is A.

7 0
3 years ago
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By what factor must the amplitude of a sound wave be decreased in order to decrease the intensity by a factor of 3?
s344n2d4d5 [400]

Answer:

Amplitude is decreased by a factor of \sqrt3 if intensity is decreased by a factor of 3.

Explanation:

Intensity of a sound wave is directly proportional to the square of its amplitude.

Therefore, if intensity is I and amplitude is A, then

I=kA^2, where, k is constant of proportionality.

Now, if intensity of sound wave is decreased by a factor of 3. So,

New intensity is, I_{new}=\frac{I}{3}

I_{new}=kA_{new}^2\\\frac{I}{3}=kA_{new}^2

Plug in kA^2 for I. This gives,

\frac{kA^2}{3}=kA_{new}^2\\A_{new}^2=\frac{A^2}{3}\\A_{new}=\sqrt{\frac{A^2}{3}}=\frac{A}{\sqrt{3}}

Therefore, amplitude is decreased by a factor of \sqrt3.

4 0
3 years ago
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