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kondor19780726 [428]
3 years ago
15

One way in which elements differ from each other is the structure of the electron cloud in each element’s atoms. In an electron

cloud, an electron that is farther away from the nucleus has
a greater charge than an electron near the nucleus.
a smaller charge than an electron near the nucleus
a higher energy than an electron near the nucleus.
a lower energy than an electron near the nucleus.
Physics
2 answers:
umka2103 [35]3 years ago
8 0

Answer:

a higher energy than an electron near the nucleus

Explanation:

STAY SAFE

AfilCa [17]3 years ago
5 0

a higher energy than an electron near the nucleus

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Calculate the magnitude of the electric field inside the solid at a distance of 9.50 cm from the center of the cavity. Express y
WITCHER [35]

Question:

A point charge of -2.14uC  is located in the center of a spherical cavity of radius 6.55cm  inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.

a) Calculate the magnitude of the electric field inside the solid at a distance of 9.50cm  from the center of the cavity.  

Express your answer using two significant figures.

Answer:

The magnitude of the electric field inside the solid at a distance of 9.50cm from the center of the cavity 3.65\times 10^5N/C

Explanation:

A point charge ,q = -2.14\times 10^{-6} C is located in the center of a spherical cavity of radius , r =6.55\times 10^{-2}  m inside an insulating spherical charged solid.  

The charge density in the solid , d = 7.35 \times 10^{-4}C/m^3.

Distance from the center of the cavity,R =9.5\times 10^{-2 }m

Volume of shell of charge= V  =(\frac{4\pi}{3})[ R^3 - r^3 ]

Charge on the shell ,Q = V \times d'

Q =(\frac{4\pi}{3})[ R^3 - r^3 ] \times d

Q = 4.1888*\times 10^{-4 }[8.57375 - 2.81011 ]\times 7.35\times 10^{-4}

Q = 4.1888\times 10^{-4} [5.76364 ] \times 7.35 \times 10^{-4}

Q =2.4143 \times 10^{-4} \times 7.35 \times 10^ { -4}

Q =1.7745 \times 10^{-6 }C

Electric field at 9.5\times 10^{-2}m due to shellE1  = \frac{k Q}{R^2}

E1 =  \frac{ 9 \times 10^9\times 1.7745\times 10^{-6 }}{ 90.25\times 10^{-4}}

E1 =1.769\times 10^6 N/C

Electric field at  9.5\times 10^{-2} due to 'q' at center E2 = \frac{kq}{R^2}

E2 =\frac{ - 9 \times 10^9\times 2.14\times 10^{-6 }}{ 90.25\times 10^{-4}}

E2 =2.134\times 10^6 N/C

The magnitude of the electric field inside the solid at a distance of 9.50cm from the center of the cavity

= E2- E1

=[  2.134  - 1.769 ]\times 10^6

= 3.65\times 10^5 N/C

8 0
3 years ago
Please help me with this please <br><br> I’ll mark you Brainly
ivolga24 [154]
I think it is option (C).

If the answer is helpful then mark me as brainly.
4 0
2 years ago
6)
tiny-mole [99]

Answer: 14.5 N

Explanation:   NEED SCRATCH PAPER: A flower pot weighing 42.0 N (newtons) is hung above a window by three ropes, each making an angle of 15.0 degrees with the vertical. What is the tension in each rope supporting the flower pot?

✓ 14.5 N

found it on the internet?

5 0
2 years ago
Acceleration is rate of change of <br>A-Position<br>B-Time<br>C-Velocity<br>D-Speed​
Drupady [299]
<h3>Answer:</h3>

[C] Velocity.

<h3>Explanation:</h3>

<u>As we know that</u>,

  • a = v - u/t

<u>where, a = acceleration, v = final velocity, u = initial velocity and t = time taken to travel</u>.

8 0
3 years ago
Read 2 more answers
What did B.F. skinnier believe drove ones behaviors
Nastasia [14]
He thought that behavior is determined by its consequences.
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3 years ago
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