An airplane is flying horizontally with a speed of 103 km/hr (278 m/s) when it drops a payload. The payload hits the ground 30 s
1 answer:
Answer:
H = 4500 m
Explanation:
- Once dropped, the payload moves along a trajectory, that can be decomposed along two directions independent each other.
- Just by convenience, we choose these directions to be coincident with the horizontal (-x) and vertical (y) axes.
- As both movements are independent each other due to both are perpendicular, in the vertical direction, the initial speed is 0.
- So, in order to find the vertical displacement at any point in time, we can use the following kinematic equation, where a=-g., and H = -Δy.
- The airpane was flying at a 4500 m altitude.
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The energy of the incident electron in keV is 5.51× 10—²² keV.
Capacity or ability to do work is termed energy. Energy exists in various forms. It can be in the form of mechanical, potential, thermal, kinetic, and many other forms. Joules is the SI of the energy. The potential energy of a system is defined as the energy stored due to its position. While kinetic energy is defined as the energy
stored due to its position.
Radius1 of the trajectory = 1.00 cm
Radius2 of the trajectory = 2.4 0 cm
The magnitude of the uniform magnetic field = 0.0440 T
A Uniform magnetic field is perpendicular to the trajectories.
The velocity of the incident electron is,
The energy of the incident electron is,
The energy in keV is,
1-kilo electron volt = 1000 electron volts
1 keV = 1000 eV
Therefore, the energy of the incident electron in keV is 5.51× 10—²² keV.
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