Answer:
Explanation:
In order to calculate the change of any quantity you must substract the initial value of that quantity from the final value of the same quantity.
The concept of momentum is defined as,
Momentum = mass×velocity
So we calculate the change of momentum as,
Momentum change = final momentum - initial momentum
= mv - mu =m(v-u)
Where v = final velocity
u = initial velocity
m = mass of the object
So to calculate the momentum change of the car,
Change in momentum of the car = 1000×(8-1) = 1000×7 = 7000 Ns
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
Resistance= Potential Difference/Current
10 Ohm= PD/ 5A
PD= 10 Ohm × 5A
PD=50
Therefore, Potential Difference is B. 50 V
<span>Total displacement =10
</span><span>Average velocity =6.7</span>
The initial speed of the automobile is 49.84km/hr
<u>Explanation:</u>
Given:
Acceleration, a = 1.77 m/s²
Time, t = 6s
Final speed, v = 88 km/h
v = 88 X 0.278 m/s
v = 24.464 m/s
Initial speed, u = ?
We know,
v = u + at
On substituting the value in the formula we get:
24.464 = u + (1.77 X 6)
24.464 = u + 10.62
u = 24.464 - 10.62 m/s
u = 13.844 m/s
Converting u = 13.844 m/s to km/hr
1 m/s = 3.6 km/hr
13.844 m/s = 13.844 X 3.6 km/hr
u = 49.84 km/hr
Therefore, the initial speed of the automobile is 49.84km/hr
