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sveticcg [70]
3 years ago
7

Does the KE of a car change more when it accelerates from 22 km/h to 32 km/h or when it accelerates from 32 km/h to 42 km/h

Physics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

The change in kinetic energy (KE) of the car is more in the second case.

Explanation:

Let the mass of the car = m

initial velocity of the first case, u = 22 km/h = 6.11 m/s

final velocity of the first case, v = 32 km/h = 8.89 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(8.89² - 6.11²)

                                                    = 20.85m J

 

initial velocity of the second case, u = 32 km/h = 8.89 m/s

final velocity of the second case, v = 42 km/h = 11.67 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(11.67² - 8.89²)

                                                    = 28.58m J

The change in kinetic energy (KE) of the car is more in the second case.

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A pendulum has 201 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
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<h2>Hello!</h2>

The answer is: 201 J of kinetic energy.

<h2>Why?</h2>

The motion of a pendulum (with no friction considered) is a continuous exchange between potential energy and kinetic energy.

So, at the highest point of its swing, the potential energy will be the maximum potential energy that the pendulum can have and the kinetic energy will be 0 since at max height the speed tends to 0.

On the opposite side, when the pendulum is at the bottom (the lowest point of its swing) the potential energy will be the minimum (tends to 0) but the kinetic energy will be the maximum.

Also, in the pendulum motion, the total energy is conserved, meaning that:

PE_{h} +KE_{h}=PE_{l} +KE_{l}\\PE=mgh\\KE=\frac{1mv^{2} }{2}

Where,

PE(h),is the potential energy at the highest point.

KE(h), is the kinetic energy at the highest point.

PE(l), is the potential energy at the lowest point (bottom of pendulum swing).

KE(l), is the kinetic energy at the lowest point (bottom of pendulum swing).

m, is the mass of the object.

g, is the acceleration of gravity.

v, is the speed of the object.

So, what is the energy at the bottom of its swing?

201J +0=0 +201J\\201J=201J

So, the pendulum has 201 of kinetic energy at the bottom of its swing.

Meaning that the energy is conserved.

Have a nice day!

7 0
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