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sveticcg [70]
3 years ago
7

Does the KE of a car change more when it accelerates from 22 km/h to 32 km/h or when it accelerates from 32 km/h to 42 km/h

Physics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

The change in kinetic energy (KE) of the car is more in the second case.

Explanation:

Let the mass of the car = m

initial velocity of the first case, u = 22 km/h = 6.11 m/s

final velocity of the first case, v = 32 km/h = 8.89 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(8.89² - 6.11²)

                                                    = 20.85m J

 

initial velocity of the second case, u = 32 km/h = 8.89 m/s

final velocity of the second case, v = 42 km/h = 11.67 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(11.67² - 8.89²)

                                                    = 28.58m J

The change in kinetic energy (KE) of the car is more in the second case.

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A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .
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\frac{GM}{r} = v^2

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PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

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From the speed it is possible to use find the formula, so

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saw5 [17]
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3 0
3 years ago
Read 2 more answers
Need help ASAP please and thank you
SashulF [63]

Answer:

C

Explanation:

Im not sure but I did somthing simalier

8 0
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