All categories

3 years ago

Does the KE of a car change more when it accelerates from 22 km/h to 32 km/h or when it accelerates from 32 km/h to 42 km/h

Physics

1 answer:

mote1985 [20]3 years ago

6 0

Answer:

The change in kinetic energy (KE) of the car is more in the second case.

Explanation:

Let the mass of the car = m

initial velocity of the first case, u = 22 km/h = 6.11 m/s

final velocity of the first case, v = 32 km/h = 8.89 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

ΔK.E = ¹/₂m(8.89² - 6.11²)

= 20.85m J

initial velocity of the second case, u = 32 km/h = 8.89 m/s

final velocity of the second case, v = 42 km/h = 11.67 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

ΔK.E = ¹/₂m(11.67² - 8.89²)

= 28.58m J

The change in kinetic energy (KE) of the car is more in the second case.

You might be interested in

If it takes 20n to move a box, how much power will be needed to move the box a diatance

solmaris [256]

The power applied to move the box anywhere is

(20 n) x (distance moved) / (time to move the distance) .

3 0

4 years ago

Fault block mountains form when large blocks of crust are and tilted along normal faults

Katarina [22]

Fault block mountains form when large blocks of crust are uplifted and tilted along normal faults. The uplifted blocks are called block mountains. They are formed by the movement of large crustal blocks<span> when forces in the Earth's crust pull it apart. Some parts of the Earth are pushed upward and others collapse down.</span>

6 0

3 years ago

A wire carries a steady current of 2.20

alina1380 [7]

By definition we know that the force is the vector product of the vector of the current by the length with the magnetic field vector. The current in this case goes in a positive "Y" direction. If we assume that the magnetic field goes in the positive "K" direction, then the result will be in the positive "X" direction. Attached solution.

5 0

3 years ago

Plzzzzzzz help me<br> 15 pt for 1st 10 for 2nd

maks197457 [2]

Mass is the right answer

8 0

3 years ago

Read 2 more answers

The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be

Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>

It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
Mathematically, T²∝a³

<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>

The time period of geosynchronous orbit is 24 hours or 1440 minutes.
As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
a1= (T1/T2)⅔×a2

= (1440/90)⅔×6780

= 43,090 km

Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

brainly.com/question/16705471

#SPJ4

6 0

2 years ago