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Juli2301 [7.4K]
3 years ago
7

Find the vertices and locate the foci for the hyperbola whose equation is given. 49x2 - 100y2 = 4900

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0
<h2>Answer:</h2>

A hyperbola is the set of all points in a plane such that  the difference of whose  distances from two distinct fixed points called foci is a positive constant. In this problem, we have the following equation:

49x^2-100y^2=4900

What if we divide the whole equation by 49 \times 100=4900? Well the result is:

\frac{1}{4900}(49x^2-100y^2=4900) \\ \\ \frac{49x^2}{4900}-\frac{100y^2}{4900}=\frac{4900}{4900} \\ \\ \frac{x^2}{100}-\frac{y^2}{49}=1 \\ \\ \boxed{\frac{x^2}{10^2}-\frac{y^2}{7^2}=1}

The standard form of the equation of the hyperbola given that the vertex lies on the origin is:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

SO THE VERTICES ARE:

\boxed{(a,0)=(10,0) \ and \ (-a,0)=(-10,0)}

Calculating the foci:

We \ know \ that \ foci \ are: \\ \\ (-c,0) \ and \ (c.0) \\ \\ Also: \\ \\ c=\sqrt{a^2+b^2} \\ \\ c=\sqrt{100+49} \therefore c=\sqrt{149}

SO THE FOCI ARE:

\boxed{(-\sqrt{149},0) \ and \ (\sqrt{149},0)}

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