We know that
m(A)u(A) = m(A)v(A) + m(B)v(B), since u(B) = 0 as B is at rest
calculate v(A) using:
Vx = Vcos∅Vx = 2.1cos(30)Vx = 1.82 m/s
1.5 x 4.5 = 1.5 x 1.82 + 3.2v(B)v(B) = 1.26 m/s
The deflection angle of B will be 30° above the positive x-axis, so:v(B) = Vcos∅V = 1.26 / cos(30)V = 1.45 m/s
the answer isthe velocity of B is 1.45 m/s
Answer:
I = 2.61 A
Explanation:
It is given that,
Power of a toaster is 300 watts
It is plugged into an outlet with a voltage of 115 volts
We need to find the current in the toaster's circuit.
The electrical power is given by the formula as follows :
P = V I
I is electric current
So, 2.61 A of current is in the toaster's circuit.
This question is incomplete.Here is complete one
Consider a telescope with a small circular aperture of diameter 2.0 centimeters.
If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers
Answer:
λ =492nm
Explanation:
Given Data
diameter=2.0 cm
angular separation=3.0x10^-5 radians
λ=?
Solution
sin(theta) = 1.22 x λ /D
λ=(0.02×sin(3.0×10⁻⁵))/1.22
λ=492nm