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jeyben [28]
2 years ago
10

A research study that proposed to describe the behaviors of high school teachers would be

Physics
2 answers:
german2 years ago
5 0

Answer:

That's a question?

Explanation:

Dnndnxnskwmem fmwo

nikdorinn [45]2 years ago
5 0

Answer:

<em>The Correct Answer is </em><u><em>D</em></u>

Explanation:

d) Descriptive

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You're driving down the highway late one night at 20 m/s when a deer steps onto the road 38 m in front of you.Your reaction time
shtirl [24]

Consider the motion of the car before brakes are applied:

v₀ = maximum initial velocity of the car before the brakes are applied

t = reaction time = 0.50 s

x₀ = distance traveled by the car before brakes are applied

since car moves at constant speed before brakes are applied

Using the equation

x₀ = v₀ t

x₀ = v₀  (0.50)


Consider the motion after brakes are applied :

v₀ = initial velocity of the car before the brakes are applied

a = acceleration = - 10 m/s²

v = final velocity of the car after it comes to stop = 0 m/s

x = stopping distance = initial distance - distance traveled before applying the brakes = 38 - x₀ = 38 - v₀  (0.50)

Using the equation

v² = v²₀ + 2 a x

inserting the values

0² = v²₀ + 2 (- 10) (38 - v₀  (0.50))

v²₀ = 20 (38 - v₀  (0.50))

v₀ = 23 m/s



3 0
2 years ago
Pls help me 10 points
lapo4ka [179]

Answer:

d is the right answer

it's was helpful to you

3 0
3 years ago
Read 2 more answers
The measure of how much salt will dissolve into 100g of water is _______________ .
Bingel [31]
The measure of how much salt will dissolve into 100g of water is _solution_ .
8 0
3 years ago
Read 2 more answers
Quinn accelerates her skateboard along a straight path from 0 m/s to 4.0 m/s
umka2103 [35]
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=2.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{2.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{2.5}

\\ \sf\longmapsto Acceleration=1.6m/s^2

8 0
2 years ago
A car is traveling at 39.7 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s 2 . If the coefficient of fricti
777dan777 [17]

Answer:

The minimum distance in which the car will stop is

x=167.38m

Explanation:

39.7\frac{mi}{h}*\frac{1km}{0.621371mi}*\frac{1000m}{1km}*\frac{1h}{3600s}=17.747\frac{m}{s}

∑F=m*a

∑F=u*m*g

The force of friction is the same value but in different direction of the force moving the car so it can stop so

F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }

a=-0.9408 \frac{m}{s^{2}}

v_{f}^{2}=v_{o}^{2}+2*a*(x_{f}-x_{o})\\v_{f}=0 \\x_{o}=0\\0=v_{o}^{2}+2*a*x_{f}\\x_{f}=\frac{v_{o}^{2}}{2*a} \\x_{f}=\frac{(-17.747\frac{m}{s})^{2}}{2*(-0.9408)} \\x_{f}=167.38m

4 0
3 years ago
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