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jeyben [28]
3 years ago
10

A research study that proposed to describe the behaviors of high school teachers would be

Physics
2 answers:
german3 years ago
5 0

Answer:

That's a question?

Explanation:

Dnndnxnskwmem fmwo

nikdorinn [45]3 years ago
5 0

Answer:

<em>The Correct Answer is </em><u><em>D</em></u>

Explanation:

d) Descriptive

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A cannon, located 60.0 m from the base of a vertical 25.0-m-tall cliff, shoots a 15-kg shell at 43.0o above the horizontal towar
Artist 52 [7]

Answer:

a)   v₀ = 32.64 m / s , b)  x = 59.68 m

Explanation:

a) This is a projectile launching exercise, we the distance and height of the cliff

         x = v₀ₓ t

         y = v_{oy} t - ½ g t²

We look for the components of speed with trigonometry

         sin 43 = v_{oy} / v₀

         cos 43 = v₀ₓ / v₀

         v_{oy} = v₀ sin 43

         v₀ₓ = v₀ cos 43

Let's look for time in the first equation and substitute in the second

         t = x / v₀ cos 43

         y = v₀ sin 43 (x / v₀ cos 43) - ½ g (x / v₀ cos 43)²

          y = x tan 43 - ½ g x² / v₀² cos² 43

          1 / v₀² = (x tan 43 - y) 2 cos² 43 / g x²

           v₀² = g x² / [(x tan 43 –y) 2 cos² 43]

Let's calculate

          v₀² = 9.8 60 2 / [(60 tan 43 - 25) 2 cos 43]

          v₀ = √ (35280 / 33.11)

          v₀ = 32.64 m / s

.b) we use the vertical distance equation with the speed found

         y = v_{oy} t - ½ g t²

         .y = v₀ sin43 t - ½ g t²

        25 = 32.64 sin 43 t - ½ 9.8 t²

        4.9 t² - 22.26 t + 25 = 0

         t² - 4.54 t + 5.10 = 0

We solve the second degree equation

         t = (4.54 ±√(4.54 2 - 4 5.1)) / 2

         t = (4.54 ± 0.46) / 2

         t₁ = 2.50 s

         t₂ = 2.04 s

The shortest time is when the cliff passes and the longest when it reaches the floor, with this time we look for the horizontal distance traveled

         x = v₀ₓ t

         x = v₀ cos 43 t

         x = 32.64 cos 43  2.50

         x = 59.68 m

8 0
3 years ago
base your answer to this question on the information below and on your knowledge of physics. A toy launcher that is used to laun
Nadya [2.5K]

Answer: v = 2.24 m/s

Explanation: The <u>Law</u> <u>of</u> <u>Conservation</u> <u>of</u> <u>Energy</u> states that total energy is constant in any process and, it cannot be created nor destroyed, only transformed.

So, in the toy launcher, the energy of the compressed spring, called <u>Elastic</u> <u>Potential</u> <u>Energy (PE)</u>, transforms into the movement of the plastic sphere, called <u>Kinetic</u> <u>Energy (KE)</u>. Since total energy must be constant:

KE_{i}+PE_{i}=KE_{f}+PE_{f}

where the terms with subscript i are related to the initial of the process and the terms with subscript f relates to the final process.

The equation is calculated as:

\frac{1}{2}kx^{2}+0=0+\frac{1}{2}mv^{2}

\frac{1}{2}kx^{2}=\frac{1}{2}mv^{2}

\frac{1}{2}50(0.1)^{2}=\frac{1}{2}(0.1)v^{2}

v^{2}=\frac{50(0.1)^{2}}{0.1}

v=\sqrt{50(0.1)}

v=\sqrt{5}

v = 2.24

The maximum speed the plastic sphere will be launched is 2.24 m/s.

3 0
3 years ago
What can increase the gravitational potential energy of a object
love history [14]

Answer:

Increase in mass and height

Explanation:

The gravitational potential energy of an object can increase if the mass and height of object is increased.

Gravitational potential energy is the energy due to the position of a body.

It is expressed as:

  Gravitational potential energy = mass x acceleration due gravity x height

Increasing mass and height will cause an increase in gravitational potential energy.

6 0
3 years ago
Question 5 of 10
Nina [5.8K]
It is D 14 MS. West. Kauehfbfnd
6 0
3 years ago
Does the epiglottis close the trachea when u swallow food
stiks02 [169]

Answer:

A flap of tissue called (the epiglottis) sits over the top of the trachea. This flap blocks food and drink from going down into the trachea when you swallow. But in some cases, food or drink can enter the trachea. It may go down as you swallow.

Explanation:

HOPE THIS HELPED :)

7 0
3 years ago
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