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3 years ago

5

The unit used to measure electric current is the ampere (A). Now, assume that the current delivered at a wall socket reaches the

value 3.8 A ten times in a time interval of 0.17 s. What is the period T with which the current at the wall socket changes?

1 answer:

pav-90 [236]3 years ago

8 0

Answer:

T = 0.017s

Explanation:

period is the time it takes a particle to make one oscillation

An electric current is periodic in nature

The current reaches 3.8A ten times.

So there must have been 10 cycles (10 periods) in 0.17s. let 'T' be the period:

$T=\frac{t}{n}$

t is the total time interval

n is the number of oscillations

$T=\frac{0.17}{10}$

10T = 0.17

T = 0.17/10 = 0.017s

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notka56 [123]

Answer:

Explanation:

In Both Physics and Math

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whereas Equation of parabola is something like this

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Math is a tool to solve Physics problems so equations are same in math and physics

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2 years ago

Una placa de cobre a 20°C tiene unas dimensiones de 65cm x 78 cm. Encuentra el área de la placa a 400°C; Coeficiente de dilataci

ValentinkaMS [17]

Answer:

El área de la placa es aproximadamente 5102.752 centímetros cuadrados.

Explanation:

Asumamos que el cambio dimensional como consecuencia de la temperatura es pequeña, entonces podemos estimar el área de la placa de cobre en función de la temperatura mediante la siguiente aproximación:

$A_{f} = w\cdot l \cdot [1 + 2\cdot \alpha\cdot (T_{f}-T_{o})]$ (1)

Donde:

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$l$ - Longitud de la placa, en centímetros.

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$T_{f}$ - Temperatura final, en grados Celsius.

Si sabemos que $w = 65\,cm$ , $l = 78\,cm$ , $\alpha = 17\times 10^{-6}\,\frac{1}{^{\circ}C}$ , $T_{o} = 20\,^{\circ}C$ and $T_{f} = 400\,^{\circ}C$ , entonces el área de la placa a la temperatura final:

$A_{f} = (65\,cm)\cdot (78\,cm)\cdot \left[1+\left(17\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (400\,^{\circ}C-20\,^{\circ}C)\right]$

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2 years ago

A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra

Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

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We suppose yi = 0

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This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

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So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)

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3 years ago

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Mrac [35]

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2 years ago

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A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric

natita [175]

Answer:

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Explanation:

The potential energy of a charge is given by:

$U=qV$

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Re-arranging the formula and using these numbers, we can find the electric potential:

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3 years ago

Read 2 more answers