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lubasha [3.4K]
3 years ago
8

A

Physics
1 answer:
Arada [10]3 years ago
4 0

Answer:

i would think c

Explanation:

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Use dimensional analysis to convert the following units. Show your work.
anyanavicka [17]

Answer:

Explanation:

conversion of 2.5 days to seconds

2.5 days =2.5 days*24 hours*3600 seconds

2.5 days=216000seconds

b) conversion of 25 km to mm

1 km=1000000 mm

therefore

25 km=25*1000000=25000000 mm

c) conversion 22 g to kg

1000 g=1 kg

therefore

22 g=22/1000=0.022 kg

4 0
4 years ago
A nonconducting sphere of radius 10 cm is charged uniformly with a density of 100 nC/m3. What is the magnitude of the potential
Flura [38]

Answer:

The answer is 3.0 V

Explanation:

the formula of the potential due to a non-conductive sphere with a uniform charge at a point at a distance x from the center of the sphere is equal to:

V1 = (2*π*k*ρ*(3*r^2 - x^2))/3

where

ρ = volume charge density = 100 nC/m^3

x = distance from center = 0

r = radius = 10 cm = 0.1 m

Thus:

V1 = (2*π*k*ρ*3*r^2)/3

for x = 4 cm = 0.04 m, we have:

V4 = (2*π*k*ρ*(3*r^2 - (0.04^2))/3 = (2*π*k*ρ*(3*r^2 - 0.0016))/3

The difference between both equations:

V1 - V4 = (2*π*k*ρ*3*r^2)/3 - (2*π*k*ρ*(3*r^2 - 0.0016))/3

V1 - V4 = (2*π*k*ρ*0.0016)/3 = (2*π*9x10^9*100x10^-9*0.0016)/3 = 3.02 V = 3 V

5 0
3 years ago
a bucket of unstretched springs (k=8 N/m) resting on the ground.Calculate the bucket's Mechanical Energy in [J}
Flura [38]

Answer:

0 J

Explanation:

The mechanical energy of a spring is given by 0.5kx^{2} where k is spring constant and x is extension of spring. Since the spring is unstretched,  its extension is zero.

#Notice that the potential energy is 0.

-Substituting spring constant,  k with 8 and extension with zero then the mechanical energy will be

0.5\times 8\times 0^{2}=0 J

6 0
3 years ago
What is the net force acting on a golf car traveling at a constant speed of 5 mph
bekas [8.4K]
Good homeworks
Good luck

4 0
3 years ago
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Juliette [100K]

Answer:

24.348mm

Explanation:

NB: I'll be attaching pictures so as to depict missing mathematical expressions or special characters which are not easily found on keyboards

K = d / €^n

Note : d represents the greek alphabet epsilion.

K = 345 / 0.02⁰.²² = 816mPa

The true strain based upon the stress of 414mPa =

€= (€/k)^1/n = (414/816)¹/⁰.²² = 0.04576

However the true relationship between true strain and length is given by

€ = ln(Li/Lo)

Making Li the subject of formula by rearranging,

Li = Lo.e^€

Li = 520e⁰.⁰⁴⁵⁷⁶

Li = 544.348mm

The amount of elongation can be calculated from

Change in L = Li - Lo = 544.348 - 520 change in L = 24.348mm.

8 0
3 years ago
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