Answer:
Explanation:
conversion of 2.5 days to seconds
2.5 days =2.5 days*24 hours*3600 seconds
2.5 days=216000seconds
b) conversion of 25 km to mm
1 km=1000000 mm
therefore
25 km=25*1000000=25000000 mm
c) conversion 22 g to kg
1000 g=1 kg
therefore
22 g=22/1000=0.022 kg
Answer:
The answer is 3.0 V
Explanation:
the formula of the potential due to a non-conductive sphere with a uniform charge at a point at a distance x from the center of the sphere is equal to:
V1 = (2*π*k*ρ*(3*r^2 - x^2))/3
where
ρ = volume charge density = 100 nC/m^3
x = distance from center = 0
r = radius = 10 cm = 0.1 m
Thus:
V1 = (2*π*k*ρ*3*r^2)/3
for x = 4 cm = 0.04 m, we have:
V4 = (2*π*k*ρ*(3*r^2 - (0.04^2))/3 = (2*π*k*ρ*(3*r^2 - 0.0016))/3
The difference between both equations:
V1 - V4 = (2*π*k*ρ*3*r^2)/3 - (2*π*k*ρ*(3*r^2 - 0.0016))/3
V1 - V4 = (2*π*k*ρ*0.0016)/3 = (2*π*9x10^9*100x10^-9*0.0016)/3 = 3.02 V = 3 V
Answer:
0 J
Explanation:
The mechanical energy of a spring is given by
where k is spring constant and x is extension of spring. Since the spring is unstretched, its extension is zero.
#Notice that the potential energy is 0.
-Substituting spring constant, k with 8 and extension with zero then the mechanical energy will be

Answer:
24.348mm
Explanation:
NB: I'll be attaching pictures so as to depict missing mathematical expressions or special characters which are not easily found on keyboards
K = d / €^n
Note : d represents the greek alphabet epsilion.
K = 345 / 0.02⁰.²² = 816mPa
The true strain based upon the stress of 414mPa =
€= (€/k)^1/n = (414/816)¹/⁰.²² = 0.04576
However the true relationship between true strain and length is given by
€ = ln(Li/Lo)
Making Li the subject of formula by rearranging,
Li = Lo.e^€
Li = 520e⁰.⁰⁴⁵⁷⁶
Li = 544.348mm
The amount of elongation can be calculated from
Change in L = Li - Lo = 544.348 - 520 change in L = 24.348mm.