Which conclusion is supported by the data in the table?

Sarah, whose mass is 40 kg, is on her way to school after a winter storm when she accidentally slips on a patch of ice whose coe

RideAnS [48]

Sarah's acceleration is $-0.49 m/s^2$

Explanation:

The force of kinetic friction acting on Sarah has a magnitude which is given by:

$F_f = \mu mg$

where

$\mu$ is the coefficient of kinetic friction

m is Sarah's mass

g is the acceleration of gravity

Moreover, according to Newton's second law of motion, we know that the net force on Sarah is equal to its mass times its acceleration:

$F=ma$

where a is the acceleration

Since the force of friction is the only force acting on Sarah, we can say that the net force is equal to the force of friction, therefore:

$F=-\mu mg = ma$

where the negative sign is due to the fact that the force of friction has a direction opposite to the motion of Sarah. Solving for a, we find

$a=-\mu g$

And substituting the following values:

$\mu = 0.05$ (coefficient of friction)

$g=9.81 m/s^2$ (acceleration of gravity)

we find:

$a=-(0.05)(9.81)=-0.49 m/s^2$

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4 0

3 years ago

Why does your hand feel cool if you spill some alcohol on it?

son4ous [18]

<span>It takes heat to make something evaporate, so it takes heat from your arm. Alcohol easily evaporates at room temperature, so it feels cool. This is also why you feel cool when getting out of the pool. The water on your skin evaporates.

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6 0

3 years ago

Read 2 more answers

Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t

stepan [7]

We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
$F=ma$
where $F=-50 N$ is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
$a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2$

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
$a= \frac{v_f^2-v_i^2}{2d}$
where
$v_f=0$ is the final speed of the sled
$v_i=5 m/s$ is the initial speed
$d$ is the distance covered

By rearranging the equation, we find d:
$d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m$

3 0

3 years ago

Which one is the greatest?

kipiarov [429]

Answer:

18kg dog walking

Explanation:

the dog walking has more inertia than the boy and girl because its gravity is pulling it down to the earth

6 0

3 years ago

A grating has 2000 slits/cm/cm. How many full spectral orders can be seen (400 to 700 nmnm) when it is illuminated by white ligh

Anton [14]

With the use of the formula SinФ = nλ / d, there are 16 spectral orders which can be seen when it is illuminated by white light.

Given that a grating has 2000 slits/cm. That is,

d = 0.01 / 2000

d = 5 x $10^{-6}$ m

The wavelength λ = (700 - 400) nm

λ = 300 x $10^{-9}$ m

To calculate how many full spectral orders that can be seen (400 to 700 nm) when it is illuminated by white light, we will use the below formula

SinФ = nλ / d

Φ = $Sin^{-1}$ (nλ / d)

When n = 1

Φ = $Sin^{-1}$ (300 x $10^{-9}$ / 5 x $10^{-6}$ )

Φ = 3.4 degrees

when n = 2

Φ = $Sin^{-1}$ (2 x 300 x $10^{-9}$ / 5 x $10^{-6}$ )

Ф = 6.9 degrees

When n = 3

Ф = $Sin^{-1}$ (3 x 300 x $10^{-9}$ / 5 x $10^{-6}$ )

When n = 16

Ф = $Sin^{-1}$ (16 x 300 x $10^{-9}$ / 5 x $10^{-6}$ )

Ф = $Sin^{-1}$ (0.96)

Ф = 73.7 degrees

when n = 17

Ф = $Sin^{-1}$ (17 x 300 x $10^{-9}$ / 5 x $10^{-6}$ )

Ф = $Sin^{-1}$ (1.05)

Ф = Error ( that is, it does not exist)

Therefore, there are 16 spectral orders which can be seen when it is illuminated by white light.

Learn more about double slit here: brainly.com/question/4449144

6 0

2 years ago