Answer:
11.64225 m
Explanation:A = 45 m/s – 15m/s / 6s
A = 5m/s^2
Answer:
The value of resistance of each resistor, R is 2.25 Ω
Explanation:
Given;
voltage across the three resistor, V = 1.5 V
power dissipated by the resistors, P = 3.00 W
the resistance of each resistor, = R
The effective resistance of the three resistors is given by;
R(effective) = R/3
Apply ohms law to determine the current delivered by the source;
V = IR
I = V/R
I = 3V/R
Also, power is calculated as;
P = IV
P = (3V/R) x V
P = 3V²/R
R = 3V² / P
R = (3 x 1.5²) / 3
R = 2.25 Ω
Therefore, the value of resistance of each resistor, R is 2.25 Ω
Answer:
2) Signal #2 is a digital signal that transmits signals in segments/intervals.
Explanation:
Signals are form of information propagating from the source to a display unit for appropriate interpretation. It can be either in a digital or analogue form.
A digital signal is a definite signal which is discrete in time and amplitude. It is mostly in the form of codes obtained from set of values. Graphically it transmits in the form of 1 and 0, showing a point of maximum amplitude (1) and minimum amplitude (0).
Analog signal is continuous signal describing the variation of two variables with respect to time.
Answer:
A vibration is the primary source of a sound.
Answer:
a. 165.5 V
b. 7.78 A
Explanation:
Here is the complete question
The RMS potential difference of an AC household outlet is 117 V. a) What is the maximum potential difference across a lamp connected to the outlet? b) If the RMS current through the lamp is 5.5 A, what is the maximun current through the lamp.
Solution
a. The maximum potential difference across the lamp V₀ = √2V₁ where V₁ = rms value of potential difference = 117 V
V₀ = √2V₁ = √2 × 117 V = 165.5 V
b. The maximum current through the lamp I₀ = √2I₁ where I₁ = rms value of current = 5.5 A
V₀ = √2V₁ = √2 × 5.5 A = 7.78 A
