Answer:
i)the segment that shows acceleration is segment A.
ii)the segment that shows that the object is slowing down is segment C
iii)the velocity of segment B is 40 meters per second
iv)the acceleration of segment B is zero, 0 meters per second square
Explanation:
Note that coordinates are written as (x,y) so the coordinates given in the question are (time, velocity)
i) acceleration is defined as the increase of velocity with time, segment A moved from origin (0,0) to (4,40) increasing velocity from 0m/s to 40m/s in 4 seconds.
ii) slowing down means that velocity is no longer increasing but decreasing with time. Segment C starts from (4,40) and ends at (10,0) which means the velocity reduces from 40m/s to 10m/s in 6 seconds.
iii) for segment B, (4,40) to (9,40), since the y-axis remains 40 for both cases, the velocity for segment B did not change, it remains 40m/s
iv) acceleration = v-u/t
where v=final velocity and u=initial velocity for segment B, t= time taken for change in velocity
(4,40) to (9,40)
acceleration = 40-40 / 9-4 = 0/5 = 0 meters per second square
